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GraphicsGrid with a Label for each Column and Row


Putting a vertical line in each Histogram using GraphicsGridComposite graphics with Row, Column, data aggregation and layout controlControl objects Sizing and placement in Graphicsgrid Vs Grid:Label each panel of GridCombining ArrayPlot and PlotGraphicsGrid Format Problem with SpanFromAboveConstructing a grid from a matrixHow to solve for the intersection points of two ellipses?How to use GraphicsGrid with ListPlots that have a PlotLegend?Rotated Row and Normal Column Headings for a GridPutting a vertical line in each Histogram using GraphicsGrid













4












$begingroup$


Is it possible to use GraphicsGrid and do something like this?



$begin{array}{cccc}
text{X} & Label1 & Label2& Label3\
Label4 & Plot1 & Plot2&Plot3\
Label5 & Plot4 & Plot5&Plot6\
Label6 & Plot7 & Plot8&Plot9\
end{array} $










share|improve this question









$endgroup$

















    4












    $begingroup$


    Is it possible to use GraphicsGrid and do something like this?



    $begin{array}{cccc}
    text{X} & Label1 & Label2& Label3\
    Label4 & Plot1 & Plot2&Plot3\
    Label5 & Plot4 & Plot5&Plot6\
    Label6 & Plot7 & Plot8&Plot9\
    end{array} $










    share|improve this question









    $endgroup$















      4












      4








      4





      $begingroup$


      Is it possible to use GraphicsGrid and do something like this?



      $begin{array}{cccc}
      text{X} & Label1 & Label2& Label3\
      Label4 & Plot1 & Plot2&Plot3\
      Label5 & Plot4 & Plot5&Plot6\
      Label6 & Plot7 & Plot8&Plot9\
      end{array} $










      share|improve this question









      $endgroup$




      Is it possible to use GraphicsGrid and do something like this?



      $begin{array}{cccc}
      text{X} & Label1 & Label2& Label3\
      Label4 & Plot1 & Plot2&Plot3\
      Label5 & Plot4 & Plot5&Plot6\
      Label6 & Plot7 & Plot8&Plot9\
      end{array} $







      graphics visualization






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked 5 hours ago









      An old man in the sea.An old man in the sea.

      1,089919




      1,089919






















          3 Answers
          3






          active

          oldest

          votes


















          3












          $begingroup$

          If you are willing to forego GraphicsGrid and give up some control over the placement of the decorations, it can be as simple as this:



          Make a 3 x 3 array of graphics (this is adopted from a previous answer}



          circles[n_] :=
          Module[{r, cntr}, r := RandomReal[.25];
          cntr := RandomReal[1, {2}];
          Graphics[
          Table[{EdgeForm[Black], Hue[RandomReal[]], Disk[cntr, r]}, n],
          PlotRange -> {{0, 1}, {0, 1}}, PlotRangeClipping -> True,
          Frame -> True]

          lines[] :=
          Module[{lf, rt},
          lf := With[{x = RandomReal[.48]}, {Red, Line[{{x, 0}, {x, 1}}]}];
          rt := With[{x = RandomReal[{.52, 1}]}, {Blue,
          Line[{{x, 0}, {x, 1}}]}];
          Graphics[{lf, rt}, PlotRange -> {{0, 1}, {0, 1}},
          PlotRangeClipping -> True, Frame -> True]]

          SeedRandom[4];
          graphics =
          Apply[
          Show,
          Partition[Transpose[{Table[circles[8], 9], Table[lines[], 9]}], 3],
          {2}];


          Make the headers:



          {colHeaders, rowHeaders} = Partition[Table[Style[Row[{"Label", i}], "TBI"], {i, 6}], 3];


          Make the grid with TableForm:



          TableForm[graphics, TableHeadings -> {rowHeaders, colHeaders}]


          grid






          share|improve this answer











          $endgroup$





















            2












            $begingroup$

            Here is an option:



            plots = Table[Table[Plot[Sin[i x + j], {x, 1, 10}], {i, 3}], {j, 3}];
            xlabels = {"", "Label 1", "Label 2", "Label 3"};
            ylabels = {"Label 4", "Label 5", "Label 6"};
            GraphicsGrid[Join[{xlabels}, Transpose[Join[{ylabels}, Transpose[plots]]]]]


            enter image description here






            share|improve this answer









            $endgroup$





















              2












              $begingroup$

              You could construct Graphics for the row and column headings. Something like this. Would have to adjust the vertical / horizontal placement of the label text.



              plotGrid = Table[Plot[Sin[x], {x, 0, 2 Pi}], 2, 2];

              plotRowHeader =
              Table[Graphics[Style[Text["Label " <> ToString[i]], 12]], {i, 2}];

              plotColumnHeader =
              Table[Graphics[Style[Text["Label " <> ToString[i]], 12]], {i, 3,
              4}] // Prepend[Graphics[Style[Text["X"], 12]]];

              graphicsGrid =
              plotGrid // Prepend[plotRowHeader] // Transpose //
              Prepend[plotColumnHeader];

              GraphicsGrid[graphicsGrid]


              enter image description here






              share|improve this answer









              $endgroup$













                Your Answer





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                3 Answers
                3






                active

                oldest

                votes








                3 Answers
                3






                active

                oldest

                votes









                active

                oldest

                votes






                active

                oldest

                votes









                3












                $begingroup$

                If you are willing to forego GraphicsGrid and give up some control over the placement of the decorations, it can be as simple as this:



                Make a 3 x 3 array of graphics (this is adopted from a previous answer}



                circles[n_] :=
                Module[{r, cntr}, r := RandomReal[.25];
                cntr := RandomReal[1, {2}];
                Graphics[
                Table[{EdgeForm[Black], Hue[RandomReal[]], Disk[cntr, r]}, n],
                PlotRange -> {{0, 1}, {0, 1}}, PlotRangeClipping -> True,
                Frame -> True]

                lines[] :=
                Module[{lf, rt},
                lf := With[{x = RandomReal[.48]}, {Red, Line[{{x, 0}, {x, 1}}]}];
                rt := With[{x = RandomReal[{.52, 1}]}, {Blue,
                Line[{{x, 0}, {x, 1}}]}];
                Graphics[{lf, rt}, PlotRange -> {{0, 1}, {0, 1}},
                PlotRangeClipping -> True, Frame -> True]]

                SeedRandom[4];
                graphics =
                Apply[
                Show,
                Partition[Transpose[{Table[circles[8], 9], Table[lines[], 9]}], 3],
                {2}];


                Make the headers:



                {colHeaders, rowHeaders} = Partition[Table[Style[Row[{"Label", i}], "TBI"], {i, 6}], 3];


                Make the grid with TableForm:



                TableForm[graphics, TableHeadings -> {rowHeaders, colHeaders}]


                grid






                share|improve this answer











                $endgroup$


















                  3












                  $begingroup$

                  If you are willing to forego GraphicsGrid and give up some control over the placement of the decorations, it can be as simple as this:



                  Make a 3 x 3 array of graphics (this is adopted from a previous answer}



                  circles[n_] :=
                  Module[{r, cntr}, r := RandomReal[.25];
                  cntr := RandomReal[1, {2}];
                  Graphics[
                  Table[{EdgeForm[Black], Hue[RandomReal[]], Disk[cntr, r]}, n],
                  PlotRange -> {{0, 1}, {0, 1}}, PlotRangeClipping -> True,
                  Frame -> True]

                  lines[] :=
                  Module[{lf, rt},
                  lf := With[{x = RandomReal[.48]}, {Red, Line[{{x, 0}, {x, 1}}]}];
                  rt := With[{x = RandomReal[{.52, 1}]}, {Blue,
                  Line[{{x, 0}, {x, 1}}]}];
                  Graphics[{lf, rt}, PlotRange -> {{0, 1}, {0, 1}},
                  PlotRangeClipping -> True, Frame -> True]]

                  SeedRandom[4];
                  graphics =
                  Apply[
                  Show,
                  Partition[Transpose[{Table[circles[8], 9], Table[lines[], 9]}], 3],
                  {2}];


                  Make the headers:



                  {colHeaders, rowHeaders} = Partition[Table[Style[Row[{"Label", i}], "TBI"], {i, 6}], 3];


                  Make the grid with TableForm:



                  TableForm[graphics, TableHeadings -> {rowHeaders, colHeaders}]


                  grid






                  share|improve this answer











                  $endgroup$
















                    3












                    3








                    3





                    $begingroup$

                    If you are willing to forego GraphicsGrid and give up some control over the placement of the decorations, it can be as simple as this:



                    Make a 3 x 3 array of graphics (this is adopted from a previous answer}



                    circles[n_] :=
                    Module[{r, cntr}, r := RandomReal[.25];
                    cntr := RandomReal[1, {2}];
                    Graphics[
                    Table[{EdgeForm[Black], Hue[RandomReal[]], Disk[cntr, r]}, n],
                    PlotRange -> {{0, 1}, {0, 1}}, PlotRangeClipping -> True,
                    Frame -> True]

                    lines[] :=
                    Module[{lf, rt},
                    lf := With[{x = RandomReal[.48]}, {Red, Line[{{x, 0}, {x, 1}}]}];
                    rt := With[{x = RandomReal[{.52, 1}]}, {Blue,
                    Line[{{x, 0}, {x, 1}}]}];
                    Graphics[{lf, rt}, PlotRange -> {{0, 1}, {0, 1}},
                    PlotRangeClipping -> True, Frame -> True]]

                    SeedRandom[4];
                    graphics =
                    Apply[
                    Show,
                    Partition[Transpose[{Table[circles[8], 9], Table[lines[], 9]}], 3],
                    {2}];


                    Make the headers:



                    {colHeaders, rowHeaders} = Partition[Table[Style[Row[{"Label", i}], "TBI"], {i, 6}], 3];


                    Make the grid with TableForm:



                    TableForm[graphics, TableHeadings -> {rowHeaders, colHeaders}]


                    grid






                    share|improve this answer











                    $endgroup$



                    If you are willing to forego GraphicsGrid and give up some control over the placement of the decorations, it can be as simple as this:



                    Make a 3 x 3 array of graphics (this is adopted from a previous answer}



                    circles[n_] :=
                    Module[{r, cntr}, r := RandomReal[.25];
                    cntr := RandomReal[1, {2}];
                    Graphics[
                    Table[{EdgeForm[Black], Hue[RandomReal[]], Disk[cntr, r]}, n],
                    PlotRange -> {{0, 1}, {0, 1}}, PlotRangeClipping -> True,
                    Frame -> True]

                    lines[] :=
                    Module[{lf, rt},
                    lf := With[{x = RandomReal[.48]}, {Red, Line[{{x, 0}, {x, 1}}]}];
                    rt := With[{x = RandomReal[{.52, 1}]}, {Blue,
                    Line[{{x, 0}, {x, 1}}]}];
                    Graphics[{lf, rt}, PlotRange -> {{0, 1}, {0, 1}},
                    PlotRangeClipping -> True, Frame -> True]]

                    SeedRandom[4];
                    graphics =
                    Apply[
                    Show,
                    Partition[Transpose[{Table[circles[8], 9], Table[lines[], 9]}], 3],
                    {2}];


                    Make the headers:



                    {colHeaders, rowHeaders} = Partition[Table[Style[Row[{"Label", i}], "TBI"], {i, 6}], 3];


                    Make the grid with TableForm:



                    TableForm[graphics, TableHeadings -> {rowHeaders, colHeaders}]


                    grid







                    share|improve this answer














                    share|improve this answer



                    share|improve this answer








                    edited 1 min ago

























                    answered 41 mins ago









                    m_goldbergm_goldberg

                    87.7k872198




                    87.7k872198























                        2












                        $begingroup$

                        Here is an option:



                        plots = Table[Table[Plot[Sin[i x + j], {x, 1, 10}], {i, 3}], {j, 3}];
                        xlabels = {"", "Label 1", "Label 2", "Label 3"};
                        ylabels = {"Label 4", "Label 5", "Label 6"};
                        GraphicsGrid[Join[{xlabels}, Transpose[Join[{ylabels}, Transpose[plots]]]]]


                        enter image description here






                        share|improve this answer









                        $endgroup$


















                          2












                          $begingroup$

                          Here is an option:



                          plots = Table[Table[Plot[Sin[i x + j], {x, 1, 10}], {i, 3}], {j, 3}];
                          xlabels = {"", "Label 1", "Label 2", "Label 3"};
                          ylabels = {"Label 4", "Label 5", "Label 6"};
                          GraphicsGrid[Join[{xlabels}, Transpose[Join[{ylabels}, Transpose[plots]]]]]


                          enter image description here






                          share|improve this answer









                          $endgroup$
















                            2












                            2








                            2





                            $begingroup$

                            Here is an option:



                            plots = Table[Table[Plot[Sin[i x + j], {x, 1, 10}], {i, 3}], {j, 3}];
                            xlabels = {"", "Label 1", "Label 2", "Label 3"};
                            ylabels = {"Label 4", "Label 5", "Label 6"};
                            GraphicsGrid[Join[{xlabels}, Transpose[Join[{ylabels}, Transpose[plots]]]]]


                            enter image description here






                            share|improve this answer









                            $endgroup$



                            Here is an option:



                            plots = Table[Table[Plot[Sin[i x + j], {x, 1, 10}], {i, 3}], {j, 3}];
                            xlabels = {"", "Label 1", "Label 2", "Label 3"};
                            ylabels = {"Label 4", "Label 5", "Label 6"};
                            GraphicsGrid[Join[{xlabels}, Transpose[Join[{ylabels}, Transpose[plots]]]]]


                            enter image description here







                            share|improve this answer












                            share|improve this answer



                            share|improve this answer










                            answered 3 hours ago









                            MelaGoMelaGo

                            4963




                            4963























                                2












                                $begingroup$

                                You could construct Graphics for the row and column headings. Something like this. Would have to adjust the vertical / horizontal placement of the label text.



                                plotGrid = Table[Plot[Sin[x], {x, 0, 2 Pi}], 2, 2];

                                plotRowHeader =
                                Table[Graphics[Style[Text["Label " <> ToString[i]], 12]], {i, 2}];

                                plotColumnHeader =
                                Table[Graphics[Style[Text["Label " <> ToString[i]], 12]], {i, 3,
                                4}] // Prepend[Graphics[Style[Text["X"], 12]]];

                                graphicsGrid =
                                plotGrid // Prepend[plotRowHeader] // Transpose //
                                Prepend[plotColumnHeader];

                                GraphicsGrid[graphicsGrid]


                                enter image description here






                                share|improve this answer









                                $endgroup$


















                                  2












                                  $begingroup$

                                  You could construct Graphics for the row and column headings. Something like this. Would have to adjust the vertical / horizontal placement of the label text.



                                  plotGrid = Table[Plot[Sin[x], {x, 0, 2 Pi}], 2, 2];

                                  plotRowHeader =
                                  Table[Graphics[Style[Text["Label " <> ToString[i]], 12]], {i, 2}];

                                  plotColumnHeader =
                                  Table[Graphics[Style[Text["Label " <> ToString[i]], 12]], {i, 3,
                                  4}] // Prepend[Graphics[Style[Text["X"], 12]]];

                                  graphicsGrid =
                                  plotGrid // Prepend[plotRowHeader] // Transpose //
                                  Prepend[plotColumnHeader];

                                  GraphicsGrid[graphicsGrid]


                                  enter image description here






                                  share|improve this answer









                                  $endgroup$
















                                    2












                                    2








                                    2





                                    $begingroup$

                                    You could construct Graphics for the row and column headings. Something like this. Would have to adjust the vertical / horizontal placement of the label text.



                                    plotGrid = Table[Plot[Sin[x], {x, 0, 2 Pi}], 2, 2];

                                    plotRowHeader =
                                    Table[Graphics[Style[Text["Label " <> ToString[i]], 12]], {i, 2}];

                                    plotColumnHeader =
                                    Table[Graphics[Style[Text["Label " <> ToString[i]], 12]], {i, 3,
                                    4}] // Prepend[Graphics[Style[Text["X"], 12]]];

                                    graphicsGrid =
                                    plotGrid // Prepend[plotRowHeader] // Transpose //
                                    Prepend[plotColumnHeader];

                                    GraphicsGrid[graphicsGrid]


                                    enter image description here






                                    share|improve this answer









                                    $endgroup$



                                    You could construct Graphics for the row and column headings. Something like this. Would have to adjust the vertical / horizontal placement of the label text.



                                    plotGrid = Table[Plot[Sin[x], {x, 0, 2 Pi}], 2, 2];

                                    plotRowHeader =
                                    Table[Graphics[Style[Text["Label " <> ToString[i]], 12]], {i, 2}];

                                    plotColumnHeader =
                                    Table[Graphics[Style[Text["Label " <> ToString[i]], 12]], {i, 3,
                                    4}] // Prepend[Graphics[Style[Text["X"], 12]]];

                                    graphicsGrid =
                                    plotGrid // Prepend[plotRowHeader] // Transpose //
                                    Prepend[plotColumnHeader];

                                    GraphicsGrid[graphicsGrid]


                                    enter image description here







                                    share|improve this answer












                                    share|improve this answer



                                    share|improve this answer










                                    answered 3 hours ago









                                    Rohit NamjoshiRohit Namjoshi

                                    1,4921213




                                    1,4921213






























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