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ErrorListPlot crops error bars


Define function that behaves almost identically to Mathematica functionWhat's the simplest way to plot an ErrorListPlot with only y error bars?Including error bars on graph in MathematicaHow do I adjust error bar tick size with ErrorListPlot?Misalignment of plot points when adding error barsError bars in BarChart3DError bars from listsPlotting error bars in both dimensions for straight line modelBarChart with error barsHow to plot data as (X,Y) points with error bars on YHow to Plot Error Bars Without Caps using ErrorListPlot













1












$begingroup$


The default behaviour of ErrorListPlot often crops error bars, as in the example below. How can this be fixed in a clean way?



Needs["ErrorBarPlots`"];
data = Table[{{x, Cos[x]}, ErrorBar[Cos[x]^2]}, {x, 0, 2 Pi}];
plot = ErrorListPlot[data, PlotRangePadding -> Scaled[.05]]


The ErrorListPlot generated by the above code










share|improve this question









$endgroup$

















    1












    $begingroup$


    The default behaviour of ErrorListPlot often crops error bars, as in the example below. How can this be fixed in a clean way?



    Needs["ErrorBarPlots`"];
    data = Table[{{x, Cos[x]}, ErrorBar[Cos[x]^2]}, {x, 0, 2 Pi}];
    plot = ErrorListPlot[data, PlotRangePadding -> Scaled[.05]]


    The ErrorListPlot generated by the above code










    share|improve this question









    $endgroup$















      1












      1








      1


      1



      $begingroup$


      The default behaviour of ErrorListPlot often crops error bars, as in the example below. How can this be fixed in a clean way?



      Needs["ErrorBarPlots`"];
      data = Table[{{x, Cos[x]}, ErrorBar[Cos[x]^2]}, {x, 0, 2 Pi}];
      plot = ErrorListPlot[data, PlotRangePadding -> Scaled[.05]]


      The ErrorListPlot generated by the above code










      share|improve this question









      $endgroup$




      The default behaviour of ErrorListPlot often crops error bars, as in the example below. How can this be fixed in a clean way?



      Needs["ErrorBarPlots`"];
      data = Table[{{x, Cos[x]}, ErrorBar[Cos[x]^2]}, {x, 0, 2 Pi}];
      plot = ErrorListPlot[data, PlotRangePadding -> Scaled[.05]]


      The ErrorListPlot generated by the above code







      plotting






      share|improve this question













      share|improve this question











      share|improve this question




      share|improve this question










      asked 3 hours ago









      TomTom

      1,243919




      1,243919






















          2 Answers
          2






          active

          oldest

          votes


















          2












          $begingroup$

          Here is my solution. Calculate the value of each data point plus (and minus) it's error bar. Then you can calculate the location of the highest (and lowest) error bar. Then use this to specify the PlotRange.



          data = Table[{{x, Cos[x]}, ErrorBar[Cos[x]^2]}, {x, 0, 2 Pi}];
          minima = #[[1]][[2]] - #[[2]][[1]] & /@ data;
          maxima = #[[1]][[2]] + #[[2]][[1]] & /@ data;
          plot = ErrorListPlot[data, PlotRange -> {Min[minima], Max[maxima]}, PlotRangePadding -> Scaled[.05]]


          ErrorListPlot generated by the above code



          We can make a nice little function that we can use in a similar way to ErrorListPlot but takes care of the PlotRange automatically as we desired. The difference here is that other optional arguments have to be grouped together into a list. I'm sure there's a nicer way to do this with optional arguments, but I don't know how to implement it.



          errorListPlot[data_, opts_] := Module[{minima, maxima},
          minima = #[[1]][[2]] - #[[2]][[1]] & /@ data;
          maxima = #[[1]][[2]] + #[[2]][[1]] & /@ data;
          ErrorListPlot[data, PlotRange -> {Min[minima], Max[maxima]}, opts]
          ]

          data = Table[{{x, Cos[x]}, ErrorBar[Cos[x]^2]}, {x, 0, 2 Pi}];
          errorListPlot[data, {PlotRangePadding -> Scaled[.05], PlotStyle -> Red}]


          ErrorListPlot generated with custom 'errorListPlot' Module defined above






          share|improve this answer











          $endgroup$





















            2












            $begingroup$

            You can just Show plot with the option PlotRange -> All:



            Show[plot, PlotRange -> All]


            enter image description here



            Why?



            plot already contains full lines which you can see by looking at plot[[1]] which contains all the graphics directives and primitives:



            Graphics[plot[[1]]]


            enter image description here



            Somehow, the FrontEnd thinks displaying the cropped version is in some sense better. You can always override the rendering choices of the FrontEnd using Show with appropriate options.






            share|improve this answer











            $endgroup$













            • $begingroup$
              Much neater! I feel like a right mug now
              $endgroup$
              – Tom
              1 hour ago











            Your Answer





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            2 Answers
            2






            active

            oldest

            votes








            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            2












            $begingroup$

            Here is my solution. Calculate the value of each data point plus (and minus) it's error bar. Then you can calculate the location of the highest (and lowest) error bar. Then use this to specify the PlotRange.



            data = Table[{{x, Cos[x]}, ErrorBar[Cos[x]^2]}, {x, 0, 2 Pi}];
            minima = #[[1]][[2]] - #[[2]][[1]] & /@ data;
            maxima = #[[1]][[2]] + #[[2]][[1]] & /@ data;
            plot = ErrorListPlot[data, PlotRange -> {Min[minima], Max[maxima]}, PlotRangePadding -> Scaled[.05]]


            ErrorListPlot generated by the above code



            We can make a nice little function that we can use in a similar way to ErrorListPlot but takes care of the PlotRange automatically as we desired. The difference here is that other optional arguments have to be grouped together into a list. I'm sure there's a nicer way to do this with optional arguments, but I don't know how to implement it.



            errorListPlot[data_, opts_] := Module[{minima, maxima},
            minima = #[[1]][[2]] - #[[2]][[1]] & /@ data;
            maxima = #[[1]][[2]] + #[[2]][[1]] & /@ data;
            ErrorListPlot[data, PlotRange -> {Min[minima], Max[maxima]}, opts]
            ]

            data = Table[{{x, Cos[x]}, ErrorBar[Cos[x]^2]}, {x, 0, 2 Pi}];
            errorListPlot[data, {PlotRangePadding -> Scaled[.05], PlotStyle -> Red}]


            ErrorListPlot generated with custom 'errorListPlot' Module defined above






            share|improve this answer











            $endgroup$


















              2












              $begingroup$

              Here is my solution. Calculate the value of each data point plus (and minus) it's error bar. Then you can calculate the location of the highest (and lowest) error bar. Then use this to specify the PlotRange.



              data = Table[{{x, Cos[x]}, ErrorBar[Cos[x]^2]}, {x, 0, 2 Pi}];
              minima = #[[1]][[2]] - #[[2]][[1]] & /@ data;
              maxima = #[[1]][[2]] + #[[2]][[1]] & /@ data;
              plot = ErrorListPlot[data, PlotRange -> {Min[minima], Max[maxima]}, PlotRangePadding -> Scaled[.05]]


              ErrorListPlot generated by the above code



              We can make a nice little function that we can use in a similar way to ErrorListPlot but takes care of the PlotRange automatically as we desired. The difference here is that other optional arguments have to be grouped together into a list. I'm sure there's a nicer way to do this with optional arguments, but I don't know how to implement it.



              errorListPlot[data_, opts_] := Module[{minima, maxima},
              minima = #[[1]][[2]] - #[[2]][[1]] & /@ data;
              maxima = #[[1]][[2]] + #[[2]][[1]] & /@ data;
              ErrorListPlot[data, PlotRange -> {Min[minima], Max[maxima]}, opts]
              ]

              data = Table[{{x, Cos[x]}, ErrorBar[Cos[x]^2]}, {x, 0, 2 Pi}];
              errorListPlot[data, {PlotRangePadding -> Scaled[.05], PlotStyle -> Red}]


              ErrorListPlot generated with custom 'errorListPlot' Module defined above






              share|improve this answer











              $endgroup$
















                2












                2








                2





                $begingroup$

                Here is my solution. Calculate the value of each data point plus (and minus) it's error bar. Then you can calculate the location of the highest (and lowest) error bar. Then use this to specify the PlotRange.



                data = Table[{{x, Cos[x]}, ErrorBar[Cos[x]^2]}, {x, 0, 2 Pi}];
                minima = #[[1]][[2]] - #[[2]][[1]] & /@ data;
                maxima = #[[1]][[2]] + #[[2]][[1]] & /@ data;
                plot = ErrorListPlot[data, PlotRange -> {Min[minima], Max[maxima]}, PlotRangePadding -> Scaled[.05]]


                ErrorListPlot generated by the above code



                We can make a nice little function that we can use in a similar way to ErrorListPlot but takes care of the PlotRange automatically as we desired. The difference here is that other optional arguments have to be grouped together into a list. I'm sure there's a nicer way to do this with optional arguments, but I don't know how to implement it.



                errorListPlot[data_, opts_] := Module[{minima, maxima},
                minima = #[[1]][[2]] - #[[2]][[1]] & /@ data;
                maxima = #[[1]][[2]] + #[[2]][[1]] & /@ data;
                ErrorListPlot[data, PlotRange -> {Min[minima], Max[maxima]}, opts]
                ]

                data = Table[{{x, Cos[x]}, ErrorBar[Cos[x]^2]}, {x, 0, 2 Pi}];
                errorListPlot[data, {PlotRangePadding -> Scaled[.05], PlotStyle -> Red}]


                ErrorListPlot generated with custom 'errorListPlot' Module defined above






                share|improve this answer











                $endgroup$



                Here is my solution. Calculate the value of each data point plus (and minus) it's error bar. Then you can calculate the location of the highest (and lowest) error bar. Then use this to specify the PlotRange.



                data = Table[{{x, Cos[x]}, ErrorBar[Cos[x]^2]}, {x, 0, 2 Pi}];
                minima = #[[1]][[2]] - #[[2]][[1]] & /@ data;
                maxima = #[[1]][[2]] + #[[2]][[1]] & /@ data;
                plot = ErrorListPlot[data, PlotRange -> {Min[minima], Max[maxima]}, PlotRangePadding -> Scaled[.05]]


                ErrorListPlot generated by the above code



                We can make a nice little function that we can use in a similar way to ErrorListPlot but takes care of the PlotRange automatically as we desired. The difference here is that other optional arguments have to be grouped together into a list. I'm sure there's a nicer way to do this with optional arguments, but I don't know how to implement it.



                errorListPlot[data_, opts_] := Module[{minima, maxima},
                minima = #[[1]][[2]] - #[[2]][[1]] & /@ data;
                maxima = #[[1]][[2]] + #[[2]][[1]] & /@ data;
                ErrorListPlot[data, PlotRange -> {Min[minima], Max[maxima]}, opts]
                ]

                data = Table[{{x, Cos[x]}, ErrorBar[Cos[x]^2]}, {x, 0, 2 Pi}];
                errorListPlot[data, {PlotRangePadding -> Scaled[.05], PlotStyle -> Red}]


                ErrorListPlot generated with custom 'errorListPlot' Module defined above







                share|improve this answer














                share|improve this answer



                share|improve this answer








                edited 2 hours ago

























                answered 3 hours ago









                TomTom

                1,243919




                1,243919























                    2












                    $begingroup$

                    You can just Show plot with the option PlotRange -> All:



                    Show[plot, PlotRange -> All]


                    enter image description here



                    Why?



                    plot already contains full lines which you can see by looking at plot[[1]] which contains all the graphics directives and primitives:



                    Graphics[plot[[1]]]


                    enter image description here



                    Somehow, the FrontEnd thinks displaying the cropped version is in some sense better. You can always override the rendering choices of the FrontEnd using Show with appropriate options.






                    share|improve this answer











                    $endgroup$













                    • $begingroup$
                      Much neater! I feel like a right mug now
                      $endgroup$
                      – Tom
                      1 hour ago
















                    2












                    $begingroup$

                    You can just Show plot with the option PlotRange -> All:



                    Show[plot, PlotRange -> All]


                    enter image description here



                    Why?



                    plot already contains full lines which you can see by looking at plot[[1]] which contains all the graphics directives and primitives:



                    Graphics[plot[[1]]]


                    enter image description here



                    Somehow, the FrontEnd thinks displaying the cropped version is in some sense better. You can always override the rendering choices of the FrontEnd using Show with appropriate options.






                    share|improve this answer











                    $endgroup$













                    • $begingroup$
                      Much neater! I feel like a right mug now
                      $endgroup$
                      – Tom
                      1 hour ago














                    2












                    2








                    2





                    $begingroup$

                    You can just Show plot with the option PlotRange -> All:



                    Show[plot, PlotRange -> All]


                    enter image description here



                    Why?



                    plot already contains full lines which you can see by looking at plot[[1]] which contains all the graphics directives and primitives:



                    Graphics[plot[[1]]]


                    enter image description here



                    Somehow, the FrontEnd thinks displaying the cropped version is in some sense better. You can always override the rendering choices of the FrontEnd using Show with appropriate options.






                    share|improve this answer











                    $endgroup$



                    You can just Show plot with the option PlotRange -> All:



                    Show[plot, PlotRange -> All]


                    enter image description here



                    Why?



                    plot already contains full lines which you can see by looking at plot[[1]] which contains all the graphics directives and primitives:



                    Graphics[plot[[1]]]


                    enter image description here



                    Somehow, the FrontEnd thinks displaying the cropped version is in some sense better. You can always override the rendering choices of the FrontEnd using Show with appropriate options.







                    share|improve this answer














                    share|improve this answer



                    share|improve this answer








                    edited 2 hours ago

























                    answered 2 hours ago









                    kglrkglr

                    185k10202420




                    185k10202420












                    • $begingroup$
                      Much neater! I feel like a right mug now
                      $endgroup$
                      – Tom
                      1 hour ago


















                    • $begingroup$
                      Much neater! I feel like a right mug now
                      $endgroup$
                      – Tom
                      1 hour ago
















                    $begingroup$
                    Much neater! I feel like a right mug now
                    $endgroup$
                    – Tom
                    1 hour ago




                    $begingroup$
                    Much neater! I feel like a right mug now
                    $endgroup$
                    – Tom
                    1 hour ago


















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