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Using lag function in mysql to get previous values



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Strange behaviour with MySQL 5.1 TO_DAYS partitioning schemaMySQL Insert into two tables using new IDsHow to arrange rows selected in MYSQL query?Unable to get the latest value added to Mysql table based on posted timeGrouping Data Using Joined Tables with Certain Distinct ValuesIs it possible to clean up duplicate entries with just SQL?Strange sort behavior on a partitioned table with a prefix indexMYSQL Including Missing Values Using the Previous Most Recent RecordMysql temp table insert from json can't handle null valuesMYSQL: How to select all attributes of all duplicate entries?





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I am trying to create MySQL dataset which has entries from previous study (surgical study with the first study having value of 1) as well for that userid. Each user can have multiple studies. I am trying to use Lag function to get previous study data. I am getting duplicate values for study 1 while trying to use the lag function.



WITH Complete_Data AS (
SELECT *
FROM Data
GROUP BY UserId, studyno
)
SELECT *, LAG(indication_of_failure, 1)
OVER (
PARTITION BY UserId
ORDER BY studyno
) prev_study_indication_of_failure
,
LAG(BCVA_State,1)
OVER (
PARTITION BY UserId
ORDER BY studyno
) prev_study_BCVA
FROM
Complete_Data
GROUP BY UserId, studyno
;


I am expecting nulls in prev_study_indication_of_failure and prev_study_BCVA when studyno = 1 but filled with values when studyno >=2.



Due to duplicate entries for studyno = 1, I am getting values in prev_study_indication_of_failure and prev_study_BCVA









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    0















    I am trying to create MySQL dataset which has entries from previous study (surgical study with the first study having value of 1) as well for that userid. Each user can have multiple studies. I am trying to use Lag function to get previous study data. I am getting duplicate values for study 1 while trying to use the lag function.



    WITH Complete_Data AS (
    SELECT *
    FROM Data
    GROUP BY UserId, studyno
    )
    SELECT *, LAG(indication_of_failure, 1)
    OVER (
    PARTITION BY UserId
    ORDER BY studyno
    ) prev_study_indication_of_failure
    ,
    LAG(BCVA_State,1)
    OVER (
    PARTITION BY UserId
    ORDER BY studyno
    ) prev_study_BCVA
    FROM
    Complete_Data
    GROUP BY UserId, studyno
    ;


    I am expecting nulls in prev_study_indication_of_failure and prev_study_BCVA when studyno = 1 but filled with values when studyno >=2.



    Due to duplicate entries for studyno = 1, I am getting values in prev_study_indication_of_failure and prev_study_BCVA









    share







    New contributor




    user1048278 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.























      0












      0








      0








      I am trying to create MySQL dataset which has entries from previous study (surgical study with the first study having value of 1) as well for that userid. Each user can have multiple studies. I am trying to use Lag function to get previous study data. I am getting duplicate values for study 1 while trying to use the lag function.



      WITH Complete_Data AS (
      SELECT *
      FROM Data
      GROUP BY UserId, studyno
      )
      SELECT *, LAG(indication_of_failure, 1)
      OVER (
      PARTITION BY UserId
      ORDER BY studyno
      ) prev_study_indication_of_failure
      ,
      LAG(BCVA_State,1)
      OVER (
      PARTITION BY UserId
      ORDER BY studyno
      ) prev_study_BCVA
      FROM
      Complete_Data
      GROUP BY UserId, studyno
      ;


      I am expecting nulls in prev_study_indication_of_failure and prev_study_BCVA when studyno = 1 but filled with values when studyno >=2.



      Due to duplicate entries for studyno = 1, I am getting values in prev_study_indication_of_failure and prev_study_BCVA









      share







      New contributor




      user1048278 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.












      I am trying to create MySQL dataset which has entries from previous study (surgical study with the first study having value of 1) as well for that userid. Each user can have multiple studies. I am trying to use Lag function to get previous study data. I am getting duplicate values for study 1 while trying to use the lag function.



      WITH Complete_Data AS (
      SELECT *
      FROM Data
      GROUP BY UserId, studyno
      )
      SELECT *, LAG(indication_of_failure, 1)
      OVER (
      PARTITION BY UserId
      ORDER BY studyno
      ) prev_study_indication_of_failure
      ,
      LAG(BCVA_State,1)
      OVER (
      PARTITION BY UserId
      ORDER BY studyno
      ) prev_study_BCVA
      FROM
      Complete_Data
      GROUP BY UserId, studyno
      ;


      I am expecting nulls in prev_study_indication_of_failure and prev_study_BCVA when studyno = 1 but filled with values when studyno >=2.



      Due to duplicate entries for studyno = 1, I am getting values in prev_study_indication_of_failure and prev_study_BCVA







      mysql





      share







      New contributor




      user1048278 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.










      share







      New contributor




      user1048278 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.








      share



      share






      New contributor




      user1048278 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      asked 4 mins ago









      user1048278user1048278

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      New contributor




      user1048278 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.





      New contributor





      user1048278 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






      user1048278 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






















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