Full outer join does not work for two small tables, error 1064get column from too many tables in mysql“Lost...
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Full outer join does not work for two small tables, error 1064
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folks.
I am currently exploring the capabilities of MySQL while doing simple exercises with diverse queries.
I was reading the following article that explains how table JOIN works:
http://www.codinghorror.com/blog/2007/10/a-visual-explanation-of-sql-joins.html
However, I am stuck at the FULL OUTER JOIN example (comprised of tableA and tableB):
tableA:
+-------+--------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-------+--------------+------+-----+---------+----------------+
| id | int(11) | NO | PRI | NULL | auto_increment |
| name | varchar(100) | YES | | NULL | |
+-------+--------------+------+-----+---------+----------------+
mysql> select * from tablea;
+----+-----------+
| id | name |
+----+-----------+
| 1 | Pirate |
| 2 | Monkey |
| 3 | Ninja |
| 4 | Spaghetti |
+----+-----------+
tableB:
+-------+--------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-------+--------------+------+-----+---------+----------------+
| id | int(11) | NO | PRI | NULL | auto_increment |
| name | varchar(100) | YES | | NULL | |
+-------+--------------+------+-----+---------+----------------+
mysql> select * from tab
+----+-------------+
| id | name |
+----+-------------+
| 1 | Rutabanga |
| 2 | Pirate |
| 3 | Darth Vader |
| 4 | Ninja |
+----+-------------+
I am trying the same as proposed in the website:
SELECT * FROM TableA
FULL OUTER JOIN TableB
ON TableA.name = TableB.name
and receive error 1064.
Does anyone have an idea what the reason could be?
Thank in advance for the assistance.
mysql join
add a comment |
folks.
I am currently exploring the capabilities of MySQL while doing simple exercises with diverse queries.
I was reading the following article that explains how table JOIN works:
http://www.codinghorror.com/blog/2007/10/a-visual-explanation-of-sql-joins.html
However, I am stuck at the FULL OUTER JOIN example (comprised of tableA and tableB):
tableA:
+-------+--------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-------+--------------+------+-----+---------+----------------+
| id | int(11) | NO | PRI | NULL | auto_increment |
| name | varchar(100) | YES | | NULL | |
+-------+--------------+------+-----+---------+----------------+
mysql> select * from tablea;
+----+-----------+
| id | name |
+----+-----------+
| 1 | Pirate |
| 2 | Monkey |
| 3 | Ninja |
| 4 | Spaghetti |
+----+-----------+
tableB:
+-------+--------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-------+--------------+------+-----+---------+----------------+
| id | int(11) | NO | PRI | NULL | auto_increment |
| name | varchar(100) | YES | | NULL | |
+-------+--------------+------+-----+---------+----------------+
mysql> select * from tab
+----+-------------+
| id | name |
+----+-------------+
| 1 | Rutabanga |
| 2 | Pirate |
| 3 | Darth Vader |
| 4 | Ninja |
+----+-------------+
I am trying the same as proposed in the website:
SELECT * FROM TableA
FULL OUTER JOIN TableB
ON TableA.name = TableB.name
and receive error 1064.
Does anyone have an idea what the reason could be?
Thank in advance for the assistance.
mysql join
add a comment |
folks.
I am currently exploring the capabilities of MySQL while doing simple exercises with diverse queries.
I was reading the following article that explains how table JOIN works:
http://www.codinghorror.com/blog/2007/10/a-visual-explanation-of-sql-joins.html
However, I am stuck at the FULL OUTER JOIN example (comprised of tableA and tableB):
tableA:
+-------+--------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-------+--------------+------+-----+---------+----------------+
| id | int(11) | NO | PRI | NULL | auto_increment |
| name | varchar(100) | YES | | NULL | |
+-------+--------------+------+-----+---------+----------------+
mysql> select * from tablea;
+----+-----------+
| id | name |
+----+-----------+
| 1 | Pirate |
| 2 | Monkey |
| 3 | Ninja |
| 4 | Spaghetti |
+----+-----------+
tableB:
+-------+--------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-------+--------------+------+-----+---------+----------------+
| id | int(11) | NO | PRI | NULL | auto_increment |
| name | varchar(100) | YES | | NULL | |
+-------+--------------+------+-----+---------+----------------+
mysql> select * from tab
+----+-------------+
| id | name |
+----+-------------+
| 1 | Rutabanga |
| 2 | Pirate |
| 3 | Darth Vader |
| 4 | Ninja |
+----+-------------+
I am trying the same as proposed in the website:
SELECT * FROM TableA
FULL OUTER JOIN TableB
ON TableA.name = TableB.name
and receive error 1064.
Does anyone have an idea what the reason could be?
Thank in advance for the assistance.
mysql join
folks.
I am currently exploring the capabilities of MySQL while doing simple exercises with diverse queries.
I was reading the following article that explains how table JOIN works:
http://www.codinghorror.com/blog/2007/10/a-visual-explanation-of-sql-joins.html
However, I am stuck at the FULL OUTER JOIN example (comprised of tableA and tableB):
tableA:
+-------+--------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-------+--------------+------+-----+---------+----------------+
| id | int(11) | NO | PRI | NULL | auto_increment |
| name | varchar(100) | YES | | NULL | |
+-------+--------------+------+-----+---------+----------------+
mysql> select * from tablea;
+----+-----------+
| id | name |
+----+-----------+
| 1 | Pirate |
| 2 | Monkey |
| 3 | Ninja |
| 4 | Spaghetti |
+----+-----------+
tableB:
+-------+--------------+------+-----+---------+----------------+
| Field | Type | Null | Key | Default | Extra |
+-------+--------------+------+-----+---------+----------------+
| id | int(11) | NO | PRI | NULL | auto_increment |
| name | varchar(100) | YES | | NULL | |
+-------+--------------+------+-----+---------+----------------+
mysql> select * from tab
+----+-------------+
| id | name |
+----+-------------+
| 1 | Rutabanga |
| 2 | Pirate |
| 3 | Darth Vader |
| 4 | Ninja |
+----+-------------+
I am trying the same as proposed in the website:
SELECT * FROM TableA
FULL OUTER JOIN TableB
ON TableA.name = TableB.name
and receive error 1064.
Does anyone have an idea what the reason could be?
Thank in advance for the assistance.
mysql join
mysql join
asked Dec 23 '13 at 14:02
query_questionquery_question
21113
21113
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
In MySql doesn't exists FULL OUTER JOIN keyword
You can try this:
SELECT * FROM TableA A
LEFT JOIN TableB B ON A.name = B.name
UNION
SELECT * FROM TableA A
RIGHT JOIN TableB B ON A.name = B.name
add a comment |
The simple reason is that MySQL has not implemented FULL
outer joins, only LEFT
and RIGHT
ones.
You can simulate the FULL
join with a UNION
of a LEFT
and a RIGHT
outer join:
SELECT TableA.*, TableB.*
FROM
TableA LEFT OUTER JOIN TableB
ON TableA.name = TableB.name
UNION
SELECT TableA.*, TableB.*
FROM
TableA RIGHT OUTER JOIN TableB
ON TableA.name = TableB.name ;
or (for improved performance) using UNION ALL
:
SELECT TableA.*, TableB.*
FROM
TableA LEFT OUTER JOIN TableB
ON TableA.name = TableB.name
UNION ALL
SELECT TableA.*, TableB.*
FROM
TableA RIGHT OUTER JOIN TableB
ON TableA.name = TableB.name
WHERE
TableA.name IS NULL ;
Both queries (UNION
and UNION ALL
) will return same results. Unless the result of the join is not unique (if it produces 2 or more identical rows). Since this question has SELECT *
, so SELECT a.*, b.*
, for this to happen, the tables should have duplicate rows, which is rather unlikely (a table with no primary or unique constraint.)
add a comment |
Yes im is healthing bodygjctihcfxjsehjcnnphguvjgtchc hfyvjgy ugswzgcczyg hctvkjvu uddvjhgv yxfvihgv uokggv hjvgvncf. Hcuvj hfjuv gciggjgfv hhfgvifdx jcfdsadwwdgug. Ydgbojgv uffv hff gxuyvjfy higvjkvf hgfvhgggvjvyvj hcyvjf hfybiffuf. Hgygchif ufugvj.gyvyv hcuyhgf yfuguffu
New contributor
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
In MySql doesn't exists FULL OUTER JOIN keyword
You can try this:
SELECT * FROM TableA A
LEFT JOIN TableB B ON A.name = B.name
UNION
SELECT * FROM TableA A
RIGHT JOIN TableB B ON A.name = B.name
add a comment |
In MySql doesn't exists FULL OUTER JOIN keyword
You can try this:
SELECT * FROM TableA A
LEFT JOIN TableB B ON A.name = B.name
UNION
SELECT * FROM TableA A
RIGHT JOIN TableB B ON A.name = B.name
add a comment |
In MySql doesn't exists FULL OUTER JOIN keyword
You can try this:
SELECT * FROM TableA A
LEFT JOIN TableB B ON A.name = B.name
UNION
SELECT * FROM TableA A
RIGHT JOIN TableB B ON A.name = B.name
In MySql doesn't exists FULL OUTER JOIN keyword
You can try this:
SELECT * FROM TableA A
LEFT JOIN TableB B ON A.name = B.name
UNION
SELECT * FROM TableA A
RIGHT JOIN TableB B ON A.name = B.name
answered Dec 23 '13 at 14:14
Joe TarasJoe Taras
556417
556417
add a comment |
add a comment |
The simple reason is that MySQL has not implemented FULL
outer joins, only LEFT
and RIGHT
ones.
You can simulate the FULL
join with a UNION
of a LEFT
and a RIGHT
outer join:
SELECT TableA.*, TableB.*
FROM
TableA LEFT OUTER JOIN TableB
ON TableA.name = TableB.name
UNION
SELECT TableA.*, TableB.*
FROM
TableA RIGHT OUTER JOIN TableB
ON TableA.name = TableB.name ;
or (for improved performance) using UNION ALL
:
SELECT TableA.*, TableB.*
FROM
TableA LEFT OUTER JOIN TableB
ON TableA.name = TableB.name
UNION ALL
SELECT TableA.*, TableB.*
FROM
TableA RIGHT OUTER JOIN TableB
ON TableA.name = TableB.name
WHERE
TableA.name IS NULL ;
Both queries (UNION
and UNION ALL
) will return same results. Unless the result of the join is not unique (if it produces 2 or more identical rows). Since this question has SELECT *
, so SELECT a.*, b.*
, for this to happen, the tables should have duplicate rows, which is rather unlikely (a table with no primary or unique constraint.)
add a comment |
The simple reason is that MySQL has not implemented FULL
outer joins, only LEFT
and RIGHT
ones.
You can simulate the FULL
join with a UNION
of a LEFT
and a RIGHT
outer join:
SELECT TableA.*, TableB.*
FROM
TableA LEFT OUTER JOIN TableB
ON TableA.name = TableB.name
UNION
SELECT TableA.*, TableB.*
FROM
TableA RIGHT OUTER JOIN TableB
ON TableA.name = TableB.name ;
or (for improved performance) using UNION ALL
:
SELECT TableA.*, TableB.*
FROM
TableA LEFT OUTER JOIN TableB
ON TableA.name = TableB.name
UNION ALL
SELECT TableA.*, TableB.*
FROM
TableA RIGHT OUTER JOIN TableB
ON TableA.name = TableB.name
WHERE
TableA.name IS NULL ;
Both queries (UNION
and UNION ALL
) will return same results. Unless the result of the join is not unique (if it produces 2 or more identical rows). Since this question has SELECT *
, so SELECT a.*, b.*
, for this to happen, the tables should have duplicate rows, which is rather unlikely (a table with no primary or unique constraint.)
add a comment |
The simple reason is that MySQL has not implemented FULL
outer joins, only LEFT
and RIGHT
ones.
You can simulate the FULL
join with a UNION
of a LEFT
and a RIGHT
outer join:
SELECT TableA.*, TableB.*
FROM
TableA LEFT OUTER JOIN TableB
ON TableA.name = TableB.name
UNION
SELECT TableA.*, TableB.*
FROM
TableA RIGHT OUTER JOIN TableB
ON TableA.name = TableB.name ;
or (for improved performance) using UNION ALL
:
SELECT TableA.*, TableB.*
FROM
TableA LEFT OUTER JOIN TableB
ON TableA.name = TableB.name
UNION ALL
SELECT TableA.*, TableB.*
FROM
TableA RIGHT OUTER JOIN TableB
ON TableA.name = TableB.name
WHERE
TableA.name IS NULL ;
Both queries (UNION
and UNION ALL
) will return same results. Unless the result of the join is not unique (if it produces 2 or more identical rows). Since this question has SELECT *
, so SELECT a.*, b.*
, for this to happen, the tables should have duplicate rows, which is rather unlikely (a table with no primary or unique constraint.)
The simple reason is that MySQL has not implemented FULL
outer joins, only LEFT
and RIGHT
ones.
You can simulate the FULL
join with a UNION
of a LEFT
and a RIGHT
outer join:
SELECT TableA.*, TableB.*
FROM
TableA LEFT OUTER JOIN TableB
ON TableA.name = TableB.name
UNION
SELECT TableA.*, TableB.*
FROM
TableA RIGHT OUTER JOIN TableB
ON TableA.name = TableB.name ;
or (for improved performance) using UNION ALL
:
SELECT TableA.*, TableB.*
FROM
TableA LEFT OUTER JOIN TableB
ON TableA.name = TableB.name
UNION ALL
SELECT TableA.*, TableB.*
FROM
TableA RIGHT OUTER JOIN TableB
ON TableA.name = TableB.name
WHERE
TableA.name IS NULL ;
Both queries (UNION
and UNION ALL
) will return same results. Unless the result of the join is not unique (if it produces 2 or more identical rows). Since this question has SELECT *
, so SELECT a.*, b.*
, for this to happen, the tables should have duplicate rows, which is rather unlikely (a table with no primary or unique constraint.)
edited Aug 28 '17 at 12:09
Paul White♦
54.1k14287460
54.1k14287460
answered Dec 23 '13 at 14:14
ypercubeᵀᴹypercubeᵀᴹ
77.9k11136219
77.9k11136219
add a comment |
add a comment |
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New contributor
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Yes im is healthing bodygjctihcfxjsehjcnnphguvjgtchc hfyvjgy ugswzgcczyg hctvkjvu uddvjhgv yxfvihgv uokggv hjvgvncf. Hcuvj hfjuv gciggjgfv hhfgvifdx jcfdsadwwdgug. Ydgbojgv uffv hff gxuyvjfy higvjkvf hgfvhgggvjvyvj hcyvjf hfybiffuf. Hgygchif ufugvj.gyvyv hcuyhgf yfuguffu
New contributor
Yes im is healthing bodygjctihcfxjsehjcnnphguvjgtchc hfyvjgy ugswzgcczyg hctvkjvu uddvjhgv yxfvihgv uokggv hjvgvncf. Hcuvj hfjuv gciggjgfv hhfgvifdx jcfdsadwwdgug. Ydgbojgv uffv hff gxuyvjfy higvjkvf hgfvhgggvjvyvj hcyvjf hfybiffuf. Hgygchif ufugvj.gyvyv hcuyhgf yfuguffu
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answered 17 mins ago
pawankumarpawankumar
1
1
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New contributor
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