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How to unnest and GROUP BY elements of a JSON array?


How to turn json array into postgres array?What does [FROM x, y] mean in Postgres?How to remove known elements from a JSON[] array in PostgreSQL?How to remove known elements from a JSON[] array in PostgreSQL?PostgreSQL, finding elements by value in numeric JSON arraysUpdate Postgres Table with Array of JSONInsert Array of JSON into Postgres TableHow do I query a JSON array stored in a JSON object?Returning a json array slice in PostgreSQLAdding array element to JSON column in PostgreSQLHow do I conditionally select elements of an array?List JSON array in MySQL as rowsGet the max value from a slice of a JSON Array?













3















Given the band table, with a json column holding an array :



id | people
---+-------------
1 | ['George', 'John']
2 | ['Thomas', 'James']
3 | ['James', 'John']


How to list the number of bands each name is part of?
Desired output:



name   | count
-------+------------
John | 2
James | 2
Thomas | 1
George | 1









share|improve this question




















  • 1





    If people is array (defined as people text[]) you could use: select name, count(*) as c from ttt, unnest(people) as name group by name;

    – ypercubeᵀᴹ
    Jun 1 '18 at 18:58






  • 1





    If it's json or jsonb, you can use json_array_elements_text() instead of unnest()

    – ypercubeᵀᴹ
    Jun 1 '18 at 19:06











  • Please remember to always disclose your version of Postgres. Ideally, add a CREATE TABLE statement with exact data types and constraints to avoid ambiguities like with json vs. jsonb.

    – Erwin Brandstetter
    Jun 4 '18 at 15:18
















3















Given the band table, with a json column holding an array :



id | people
---+-------------
1 | ['George', 'John']
2 | ['Thomas', 'James']
3 | ['James', 'John']


How to list the number of bands each name is part of?
Desired output:



name   | count
-------+------------
John | 2
James | 2
Thomas | 1
George | 1









share|improve this question




















  • 1





    If people is array (defined as people text[]) you could use: select name, count(*) as c from ttt, unnest(people) as name group by name;

    – ypercubeᵀᴹ
    Jun 1 '18 at 18:58






  • 1





    If it's json or jsonb, you can use json_array_elements_text() instead of unnest()

    – ypercubeᵀᴹ
    Jun 1 '18 at 19:06











  • Please remember to always disclose your version of Postgres. Ideally, add a CREATE TABLE statement with exact data types and constraints to avoid ambiguities like with json vs. jsonb.

    – Erwin Brandstetter
    Jun 4 '18 at 15:18














3












3








3








Given the band table, with a json column holding an array :



id | people
---+-------------
1 | ['George', 'John']
2 | ['Thomas', 'James']
3 | ['James', 'John']


How to list the number of bands each name is part of?
Desired output:



name   | count
-------+------------
John | 2
James | 2
Thomas | 1
George | 1









share|improve this question
















Given the band table, with a json column holding an array :



id | people
---+-------------
1 | ['George', 'John']
2 | ['Thomas', 'James']
3 | ['James', 'John']


How to list the number of bands each name is part of?
Desired output:



name   | count
-------+------------
John | 2
James | 2
Thomas | 1
George | 1






postgresql group-by json array






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Jun 4 '18 at 15:23









Erwin Brandstetter

92.7k9176291




92.7k9176291










asked Jun 1 '18 at 18:51









BaxBax

1488




1488








  • 1





    If people is array (defined as people text[]) you could use: select name, count(*) as c from ttt, unnest(people) as name group by name;

    – ypercubeᵀᴹ
    Jun 1 '18 at 18:58






  • 1





    If it's json or jsonb, you can use json_array_elements_text() instead of unnest()

    – ypercubeᵀᴹ
    Jun 1 '18 at 19:06











  • Please remember to always disclose your version of Postgres. Ideally, add a CREATE TABLE statement with exact data types and constraints to avoid ambiguities like with json vs. jsonb.

    – Erwin Brandstetter
    Jun 4 '18 at 15:18














  • 1





    If people is array (defined as people text[]) you could use: select name, count(*) as c from ttt, unnest(people) as name group by name;

    – ypercubeᵀᴹ
    Jun 1 '18 at 18:58






  • 1





    If it's json or jsonb, you can use json_array_elements_text() instead of unnest()

    – ypercubeᵀᴹ
    Jun 1 '18 at 19:06











  • Please remember to always disclose your version of Postgres. Ideally, add a CREATE TABLE statement with exact data types and constraints to avoid ambiguities like with json vs. jsonb.

    – Erwin Brandstetter
    Jun 4 '18 at 15:18








1




1





If people is array (defined as people text[]) you could use: select name, count(*) as c from ttt, unnest(people) as name group by name;

– ypercubeᵀᴹ
Jun 1 '18 at 18:58





If people is array (defined as people text[]) you could use: select name, count(*) as c from ttt, unnest(people) as name group by name;

– ypercubeᵀᴹ
Jun 1 '18 at 18:58




1




1





If it's json or jsonb, you can use json_array_elements_text() instead of unnest()

– ypercubeᵀᴹ
Jun 1 '18 at 19:06





If it's json or jsonb, you can use json_array_elements_text() instead of unnest()

– ypercubeᵀᴹ
Jun 1 '18 at 19:06













Please remember to always disclose your version of Postgres. Ideally, add a CREATE TABLE statement with exact data types and constraints to avoid ambiguities like with json vs. jsonb.

– Erwin Brandstetter
Jun 4 '18 at 15:18





Please remember to always disclose your version of Postgres. Ideally, add a CREATE TABLE statement with exact data types and constraints to avoid ambiguities like with json vs. jsonb.

– Erwin Brandstetter
Jun 4 '18 at 15:18










3 Answers
3






active

oldest

votes


















3














The data type of the column people is json, as is the result of json_array_elements(people). And there is no equality operator (=) for the data type json. So you also cannot run GROUP BY on it. More:




  • How to remove known elements from a JSON[] array in PostgreSQL?


jsonb has an equality operator, so the "workaround" in your answer is to cast to jsonb and use the equivalent jsonb_array_elements(). The cast adds cost:



jsonb_array_elements(people::jsonb)


Since Postgres 9.4 we also have json_array_elements_text(json) returning array elements as text. Related:




  • How to turn json array into postgres array?


So:



SELECT p.name, count(*) AS c
FROM band b, json_array_elements_text(b.people) p(name)
GROUP BY p.name;


It seems more convenient to get names as text instead of jsonb objects (double-quoted in text representation) and your "desired output" indicates you want / need text in the result to begin with.



GROUP BY on text data is also cheaper than on jsonb, so this alternative "workaround" should be faster for two reasons. (Test with EXPLAIN (ANALYZE, TIMING OFF).)



For the record, there was nothing wrong with your original answer. The comma (,) is just as "correct" as CROSS JOIN LATERAL. Having been defined earlier in standard SQL does no make it inferior. See:




  • What does [FROM x, y] mean in Postgres?


Neither is it more portable to other RDBMS, and since jsonb_array_elements() or json_array_elements_text() aren't portable to other RDBMS to begin with, that's also irrelevant. The short query does not get any clearer with CROSS JOIN LATERAL IMO, but the last bit is just my personal opinion.



I used the more explicit table and column alias p(name) and the table-qualified reference p.name to defend against possible duplicate names. name is such a common word, it might also pop up as column name in the underlying table band, in which case it would silently resolve to band.name. The simple form json_array_elements_text(people) name only attaches a table alias, the column name is still value, as returned from the function. But name resolves to it's single column value when used in the SELECT list. It happens to work as expected. But a true column name name (if band.name should exist) would bind first. While that won't bite in the given example, it can be a a loaded foot gun in other cases.



Don't use the generic "name" as identifier to begin with. Maybe that was just for the simple test case.





If the column people can hold anything but a plain JSON array, either query would trigger an exception. If you cannot guarantee data integrity, you might want to defend with json_typeof():



SELECT p.name, count(*) AS c
FROM band b, json_array_elements_text(b.people) p(name)
WHERE json_typeof(b.people) = 'array'
GROUP BY 1; -- optional short syntax since you seem to prefer short syntax


Excludes violating rows from the query.



Related:




  • When can we use an identifier number instead of its name in PostgreSQL?






share|improve this answer

































    3














    Based on @ypercubeᵀᴹ comment I ended up with :



    SELECT name, count(*) as c
    FROM band
    CROSS JOIN LATERAL jsonb_array_elements(people::jsonb) as name
    GROUP BY name;


    Just used jsonb_array_elements instead of unnest.






    share|improve this answer





















    • 1





      @See my update to your syntax for the newer way to do this.

      – Evan Carroll
      Jun 1 '18 at 19:18



















    0














    For someone in mysql
    SELECT
    JSON_EXTRACT(people, CONCAT('$[', idx, ']')) AS name, count(*) as count
    FROM yourtable
    JOIN subtable AS indexes
    WHERE JSON_EXTRACT(people, CONCAT('$[', idx, '].id')) IS NOT NULL
    group by name
    .........
    with subtable like: Colum: idx, row: 0,1,2,3,4,5,6,7,8,9......................





    share








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      3 Answers
      3






      active

      oldest

      votes








      3 Answers
      3






      active

      oldest

      votes









      active

      oldest

      votes






      active

      oldest

      votes









      3














      The data type of the column people is json, as is the result of json_array_elements(people). And there is no equality operator (=) for the data type json. So you also cannot run GROUP BY on it. More:




      • How to remove known elements from a JSON[] array in PostgreSQL?


      jsonb has an equality operator, so the "workaround" in your answer is to cast to jsonb and use the equivalent jsonb_array_elements(). The cast adds cost:



      jsonb_array_elements(people::jsonb)


      Since Postgres 9.4 we also have json_array_elements_text(json) returning array elements as text. Related:




      • How to turn json array into postgres array?


      So:



      SELECT p.name, count(*) AS c
      FROM band b, json_array_elements_text(b.people) p(name)
      GROUP BY p.name;


      It seems more convenient to get names as text instead of jsonb objects (double-quoted in text representation) and your "desired output" indicates you want / need text in the result to begin with.



      GROUP BY on text data is also cheaper than on jsonb, so this alternative "workaround" should be faster for two reasons. (Test with EXPLAIN (ANALYZE, TIMING OFF).)



      For the record, there was nothing wrong with your original answer. The comma (,) is just as "correct" as CROSS JOIN LATERAL. Having been defined earlier in standard SQL does no make it inferior. See:




      • What does [FROM x, y] mean in Postgres?


      Neither is it more portable to other RDBMS, and since jsonb_array_elements() or json_array_elements_text() aren't portable to other RDBMS to begin with, that's also irrelevant. The short query does not get any clearer with CROSS JOIN LATERAL IMO, but the last bit is just my personal opinion.



      I used the more explicit table and column alias p(name) and the table-qualified reference p.name to defend against possible duplicate names. name is such a common word, it might also pop up as column name in the underlying table band, in which case it would silently resolve to band.name. The simple form json_array_elements_text(people) name only attaches a table alias, the column name is still value, as returned from the function. But name resolves to it's single column value when used in the SELECT list. It happens to work as expected. But a true column name name (if band.name should exist) would bind first. While that won't bite in the given example, it can be a a loaded foot gun in other cases.



      Don't use the generic "name" as identifier to begin with. Maybe that was just for the simple test case.





      If the column people can hold anything but a plain JSON array, either query would trigger an exception. If you cannot guarantee data integrity, you might want to defend with json_typeof():



      SELECT p.name, count(*) AS c
      FROM band b, json_array_elements_text(b.people) p(name)
      WHERE json_typeof(b.people) = 'array'
      GROUP BY 1; -- optional short syntax since you seem to prefer short syntax


      Excludes violating rows from the query.



      Related:




      • When can we use an identifier number instead of its name in PostgreSQL?






      share|improve this answer






























        3














        The data type of the column people is json, as is the result of json_array_elements(people). And there is no equality operator (=) for the data type json. So you also cannot run GROUP BY on it. More:




        • How to remove known elements from a JSON[] array in PostgreSQL?


        jsonb has an equality operator, so the "workaround" in your answer is to cast to jsonb and use the equivalent jsonb_array_elements(). The cast adds cost:



        jsonb_array_elements(people::jsonb)


        Since Postgres 9.4 we also have json_array_elements_text(json) returning array elements as text. Related:




        • How to turn json array into postgres array?


        So:



        SELECT p.name, count(*) AS c
        FROM band b, json_array_elements_text(b.people) p(name)
        GROUP BY p.name;


        It seems more convenient to get names as text instead of jsonb objects (double-quoted in text representation) and your "desired output" indicates you want / need text in the result to begin with.



        GROUP BY on text data is also cheaper than on jsonb, so this alternative "workaround" should be faster for two reasons. (Test with EXPLAIN (ANALYZE, TIMING OFF).)



        For the record, there was nothing wrong with your original answer. The comma (,) is just as "correct" as CROSS JOIN LATERAL. Having been defined earlier in standard SQL does no make it inferior. See:




        • What does [FROM x, y] mean in Postgres?


        Neither is it more portable to other RDBMS, and since jsonb_array_elements() or json_array_elements_text() aren't portable to other RDBMS to begin with, that's also irrelevant. The short query does not get any clearer with CROSS JOIN LATERAL IMO, but the last bit is just my personal opinion.



        I used the more explicit table and column alias p(name) and the table-qualified reference p.name to defend against possible duplicate names. name is such a common word, it might also pop up as column name in the underlying table band, in which case it would silently resolve to band.name. The simple form json_array_elements_text(people) name only attaches a table alias, the column name is still value, as returned from the function. But name resolves to it's single column value when used in the SELECT list. It happens to work as expected. But a true column name name (if band.name should exist) would bind first. While that won't bite in the given example, it can be a a loaded foot gun in other cases.



        Don't use the generic "name" as identifier to begin with. Maybe that was just for the simple test case.





        If the column people can hold anything but a plain JSON array, either query would trigger an exception. If you cannot guarantee data integrity, you might want to defend with json_typeof():



        SELECT p.name, count(*) AS c
        FROM band b, json_array_elements_text(b.people) p(name)
        WHERE json_typeof(b.people) = 'array'
        GROUP BY 1; -- optional short syntax since you seem to prefer short syntax


        Excludes violating rows from the query.



        Related:




        • When can we use an identifier number instead of its name in PostgreSQL?






        share|improve this answer




























          3












          3








          3







          The data type of the column people is json, as is the result of json_array_elements(people). And there is no equality operator (=) for the data type json. So you also cannot run GROUP BY on it. More:




          • How to remove known elements from a JSON[] array in PostgreSQL?


          jsonb has an equality operator, so the "workaround" in your answer is to cast to jsonb and use the equivalent jsonb_array_elements(). The cast adds cost:



          jsonb_array_elements(people::jsonb)


          Since Postgres 9.4 we also have json_array_elements_text(json) returning array elements as text. Related:




          • How to turn json array into postgres array?


          So:



          SELECT p.name, count(*) AS c
          FROM band b, json_array_elements_text(b.people) p(name)
          GROUP BY p.name;


          It seems more convenient to get names as text instead of jsonb objects (double-quoted in text representation) and your "desired output" indicates you want / need text in the result to begin with.



          GROUP BY on text data is also cheaper than on jsonb, so this alternative "workaround" should be faster for two reasons. (Test with EXPLAIN (ANALYZE, TIMING OFF).)



          For the record, there was nothing wrong with your original answer. The comma (,) is just as "correct" as CROSS JOIN LATERAL. Having been defined earlier in standard SQL does no make it inferior. See:




          • What does [FROM x, y] mean in Postgres?


          Neither is it more portable to other RDBMS, and since jsonb_array_elements() or json_array_elements_text() aren't portable to other RDBMS to begin with, that's also irrelevant. The short query does not get any clearer with CROSS JOIN LATERAL IMO, but the last bit is just my personal opinion.



          I used the more explicit table and column alias p(name) and the table-qualified reference p.name to defend against possible duplicate names. name is such a common word, it might also pop up as column name in the underlying table band, in which case it would silently resolve to band.name. The simple form json_array_elements_text(people) name only attaches a table alias, the column name is still value, as returned from the function. But name resolves to it's single column value when used in the SELECT list. It happens to work as expected. But a true column name name (if band.name should exist) would bind first. While that won't bite in the given example, it can be a a loaded foot gun in other cases.



          Don't use the generic "name" as identifier to begin with. Maybe that was just for the simple test case.





          If the column people can hold anything but a plain JSON array, either query would trigger an exception. If you cannot guarantee data integrity, you might want to defend with json_typeof():



          SELECT p.name, count(*) AS c
          FROM band b, json_array_elements_text(b.people) p(name)
          WHERE json_typeof(b.people) = 'array'
          GROUP BY 1; -- optional short syntax since you seem to prefer short syntax


          Excludes violating rows from the query.



          Related:




          • When can we use an identifier number instead of its name in PostgreSQL?






          share|improve this answer















          The data type of the column people is json, as is the result of json_array_elements(people). And there is no equality operator (=) for the data type json. So you also cannot run GROUP BY on it. More:




          • How to remove known elements from a JSON[] array in PostgreSQL?


          jsonb has an equality operator, so the "workaround" in your answer is to cast to jsonb and use the equivalent jsonb_array_elements(). The cast adds cost:



          jsonb_array_elements(people::jsonb)


          Since Postgres 9.4 we also have json_array_elements_text(json) returning array elements as text. Related:




          • How to turn json array into postgres array?


          So:



          SELECT p.name, count(*) AS c
          FROM band b, json_array_elements_text(b.people) p(name)
          GROUP BY p.name;


          It seems more convenient to get names as text instead of jsonb objects (double-quoted in text representation) and your "desired output" indicates you want / need text in the result to begin with.



          GROUP BY on text data is also cheaper than on jsonb, so this alternative "workaround" should be faster for two reasons. (Test with EXPLAIN (ANALYZE, TIMING OFF).)



          For the record, there was nothing wrong with your original answer. The comma (,) is just as "correct" as CROSS JOIN LATERAL. Having been defined earlier in standard SQL does no make it inferior. See:




          • What does [FROM x, y] mean in Postgres?


          Neither is it more portable to other RDBMS, and since jsonb_array_elements() or json_array_elements_text() aren't portable to other RDBMS to begin with, that's also irrelevant. The short query does not get any clearer with CROSS JOIN LATERAL IMO, but the last bit is just my personal opinion.



          I used the more explicit table and column alias p(name) and the table-qualified reference p.name to defend against possible duplicate names. name is such a common word, it might also pop up as column name in the underlying table band, in which case it would silently resolve to band.name. The simple form json_array_elements_text(people) name only attaches a table alias, the column name is still value, as returned from the function. But name resolves to it's single column value when used in the SELECT list. It happens to work as expected. But a true column name name (if band.name should exist) would bind first. While that won't bite in the given example, it can be a a loaded foot gun in other cases.



          Don't use the generic "name" as identifier to begin with. Maybe that was just for the simple test case.





          If the column people can hold anything but a plain JSON array, either query would trigger an exception. If you cannot guarantee data integrity, you might want to defend with json_typeof():



          SELECT p.name, count(*) AS c
          FROM band b, json_array_elements_text(b.people) p(name)
          WHERE json_typeof(b.people) = 'array'
          GROUP BY 1; -- optional short syntax since you seem to prefer short syntax


          Excludes violating rows from the query.



          Related:




          • When can we use an identifier number instead of its name in PostgreSQL?







          share|improve this answer














          share|improve this answer



          share|improve this answer








          edited Jun 4 '18 at 15:47

























          answered Jun 4 '18 at 15:06









          Erwin BrandstetterErwin Brandstetter

          92.7k9176291




          92.7k9176291

























              3














              Based on @ypercubeᵀᴹ comment I ended up with :



              SELECT name, count(*) as c
              FROM band
              CROSS JOIN LATERAL jsonb_array_elements(people::jsonb) as name
              GROUP BY name;


              Just used jsonb_array_elements instead of unnest.






              share|improve this answer





















              • 1





                @See my update to your syntax for the newer way to do this.

                – Evan Carroll
                Jun 1 '18 at 19:18
















              3














              Based on @ypercubeᵀᴹ comment I ended up with :



              SELECT name, count(*) as c
              FROM band
              CROSS JOIN LATERAL jsonb_array_elements(people::jsonb) as name
              GROUP BY name;


              Just used jsonb_array_elements instead of unnest.






              share|improve this answer





















              • 1





                @See my update to your syntax for the newer way to do this.

                – Evan Carroll
                Jun 1 '18 at 19:18














              3












              3








              3







              Based on @ypercubeᵀᴹ comment I ended up with :



              SELECT name, count(*) as c
              FROM band
              CROSS JOIN LATERAL jsonb_array_elements(people::jsonb) as name
              GROUP BY name;


              Just used jsonb_array_elements instead of unnest.






              share|improve this answer















              Based on @ypercubeᵀᴹ comment I ended up with :



              SELECT name, count(*) as c
              FROM band
              CROSS JOIN LATERAL jsonb_array_elements(people::jsonb) as name
              GROUP BY name;


              Just used jsonb_array_elements instead of unnest.







              share|improve this answer














              share|improve this answer



              share|improve this answer








              edited Jun 1 '18 at 19:31

























              answered Jun 1 '18 at 19:06









              BaxBax

              1488




              1488








              • 1





                @See my update to your syntax for the newer way to do this.

                – Evan Carroll
                Jun 1 '18 at 19:18














              • 1





                @See my update to your syntax for the newer way to do this.

                – Evan Carroll
                Jun 1 '18 at 19:18








              1




              1





              @See my update to your syntax for the newer way to do this.

              – Evan Carroll
              Jun 1 '18 at 19:18





              @See my update to your syntax for the newer way to do this.

              – Evan Carroll
              Jun 1 '18 at 19:18











              0














              For someone in mysql
              SELECT
              JSON_EXTRACT(people, CONCAT('$[', idx, ']')) AS name, count(*) as count
              FROM yourtable
              JOIN subtable AS indexes
              WHERE JSON_EXTRACT(people, CONCAT('$[', idx, '].id')) IS NOT NULL
              group by name
              .........
              with subtable like: Colum: idx, row: 0,1,2,3,4,5,6,7,8,9......................





              share








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                0














                For someone in mysql
                SELECT
                JSON_EXTRACT(people, CONCAT('$[', idx, ']')) AS name, count(*) as count
                FROM yourtable
                JOIN subtable AS indexes
                WHERE JSON_EXTRACT(people, CONCAT('$[', idx, '].id')) IS NOT NULL
                group by name
                .........
                with subtable like: Colum: idx, row: 0,1,2,3,4,5,6,7,8,9......................





                share








                New contributor




                Long Aivy is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                Check out our Code of Conduct.























                  0












                  0








                  0







                  For someone in mysql
                  SELECT
                  JSON_EXTRACT(people, CONCAT('$[', idx, ']')) AS name, count(*) as count
                  FROM yourtable
                  JOIN subtable AS indexes
                  WHERE JSON_EXTRACT(people, CONCAT('$[', idx, '].id')) IS NOT NULL
                  group by name
                  .........
                  with subtable like: Colum: idx, row: 0,1,2,3,4,5,6,7,8,9......................





                  share








                  New contributor




                  Long Aivy is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.










                  For someone in mysql
                  SELECT
                  JSON_EXTRACT(people, CONCAT('$[', idx, ']')) AS name, count(*) as count
                  FROM yourtable
                  JOIN subtable AS indexes
                  WHERE JSON_EXTRACT(people, CONCAT('$[', idx, '].id')) IS NOT NULL
                  group by name
                  .........
                  with subtable like: Colum: idx, row: 0,1,2,3,4,5,6,7,8,9......................






                  share








                  New contributor




                  Long Aivy is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.








                  share


                  share






                  New contributor




                  Long Aivy is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.









                  answered 6 mins ago









                  Long AivyLong Aivy

                  1




                  1




                  New contributor




                  Long Aivy is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.





                  New contributor





                  Long Aivy is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.






                  Long Aivy is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                  Check out our Code of Conduct.






























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