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Convert seconds to minutes

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1

0

I currently have a function that prints the position and duration from cmus and formats it like "1/500". The issue I'm having is that I would like the position and duration data to be presented in minutes as opposed to seconds (0:01/8:20 instead of 1/500) but I'm out of ideas on how to achieve this.

Currently the relevant part of the function looks like this:

print_music(){

    if ps -C cmus > /dev/null; then

        position=`cmus-remote -Q |

            grep --text '^position' |

            sed -e 's/position //' |

            awk '{gsub("position ", "");print}'`

        duration=`cmus-remote -Q |

            grep --text '^duration' |

            sed -e 's/duration //' |

            awk '{gsub("duration ", "");print}'`

        echo "[$position/$duration]"; else echo "";

    fi

}

bash awk

share|improve this question

edited 2 hours ago

αғsнιη

17.1k103069

asked 3 hours ago

JoeJoe

173

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Is this stackoverflow.com/q/13422743/4023950 what you need?
  
  – αғsнιη
  2 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Using date -d@$variable +%-M%S does the conversion but unlike @glenn jackman solution, date will wrap to 0:00 at 3,600 secs.
  
  – bu5hman
  2 hours ago
  
  
  

  
  
  
  

add a comment | 

1

0

I currently have a function that prints the position and duration from cmus and formats it like "1/500". The issue I'm having is that I would like the position and duration data to be presented in minutes as opposed to seconds (0:01/8:20 instead of 1/500) but I'm out of ideas on how to achieve this.

Currently the relevant part of the function looks like this:

print_music(){

    if ps -C cmus > /dev/null; then

        position=`cmus-remote -Q |

            grep --text '^position' |

            sed -e 's/position //' |

            awk '{gsub("position ", "");print}'`

        duration=`cmus-remote -Q |

            grep --text '^duration' |

            sed -e 's/duration //' |

            awk '{gsub("duration ", "");print}'`

        echo "[$position/$duration]"; else echo "";

    fi

}

bash awk

share|improve this question

edited 2 hours ago

αғsнιη

17.1k103069

asked 3 hours ago

JoeJoe

173

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Is this stackoverflow.com/q/13422743/4023950 what you need?
  
  – αғsнιη
  2 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Using date -d@$variable +%-M%S does the conversion but unlike @glenn jackman solution, date will wrap to 0:00 at 3,600 secs.
  
  – bu5hman
  2 hours ago
  
  
  

  
  
  
  

add a comment | 

I currently have a function that prints the position and duration from cmus and formats it like "1/500". The issue I'm having is that I would like the position and duration data to be presented in minutes as opposed to seconds (0:01/8:20 instead of 1/500) but I'm out of ideas on how to achieve this.

Currently the relevant part of the function looks like this:

print_music(){

    if ps -C cmus > /dev/null; then

        position=`cmus-remote -Q |

            grep --text '^position' |

            sed -e 's/position //' |

            awk '{gsub("position ", "");print}'`

        duration=`cmus-remote -Q |

            grep --text '^duration' |

            sed -e 's/duration //' |

            awk '{gsub("duration ", "");print}'`

        echo "[$position/$duration]"; else echo "";

    fi

}

bash awk

share|improve this question

edited 2 hours ago

αғsнιη

17.1k103069

asked 3 hours ago

JoeJoe

173

print_music(){

    if ps -C cmus > /dev/null; then

        position=`cmus-remote -Q |

            grep --text '^position' |

            sed -e 's/position //' |

            awk '{gsub("position ", "");print}'`

        duration=`cmus-remote -Q |

            grep --text '^duration' |

            sed -e 's/duration //' |

            awk '{gsub("duration ", "");print}'`

        echo "[$position/$duration]"; else echo "";

    fi

}

share|improve this question

edited 2 hours ago

αғsнιη

17.1k103069

asked 3 hours ago

JoeJoe

173

share|improve this question

edited 2 hours ago

αғsнιη

17.1k103069

asked 3 hours ago

JoeJoe

173

edited 2 hours ago

αғsнιη

17.1k103069

edited 2 hours ago

αғsнιη

17.1k103069

asked 3 hours ago

JoeJoe

173

asked 3 hours ago

JoeJoe

173

1 Answer
1

active

oldest

votes

4

This will help you:

sec2min() { printf "%d:%02d" "$((10#$1 / 60))" "$((10#$1 % 60))"; }

$ sec2min 500

8:20

$ sec2min 1

0:01

share|improve this answer

answered 2 hours ago

glenn jackmanglenn jackman

52.9k573114

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks! That's working perfectly :)
  
  – Joe
  15 mins ago
  

  
  
  
  

add a comment | 

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4

This will help you:

sec2min() { printf "%d:%02d" "$((10#$1 / 60))" "$((10#$1 % 60))"; }

$ sec2min 500

8:20

$ sec2min 1

0:01

share|improve this answer

answered 2 hours ago

glenn jackmanglenn jackman

52.9k573114

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks! That's working perfectly :)
  
  – Joe
  15 mins ago
  

  
  
  
  

add a comment | 

4

This will help you:

sec2min() { printf "%d:%02d" "$((10#$1 / 60))" "$((10#$1 % 60))"; }

$ sec2min 500

8:20

$ sec2min 1

0:01

share|improve this answer

answered 2 hours ago

glenn jackmanglenn jackman

52.9k573114

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks! That's working perfectly :)
  
  – Joe
  15 mins ago
  

  
  
  
  

add a comment | 

This will help you:

sec2min() { printf "%d:%02d" "$((10#$1 / 60))" "$((10#$1 % 60))"; }

$ sec2min 500

8:20

$ sec2min 1

0:01

share|improve this answer

answered 2 hours ago

glenn jackmanglenn jackman

52.9k573114

sec2min() { printf "%d:%02d" "$((10#$1 / 60))" "$((10#$1 % 60))"; }

$ sec2min 500

8:20

$ sec2min 1

0:01

share|improve this answer

answered 2 hours ago

glenn jackmanglenn jackman

52.9k573114

answered 2 hours ago

glenn jackmanglenn jackman

52.9k573114

answered 2 hours ago

glenn jackmanglenn jackman

52.9k573114