API Access HTML/JavascriptHow do I get a list of the transactions of an address using TzScan API v3?How do I...
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API Access HTML/Javascript
How do I get a list of the transactions of an address using TzScan API v3?How do I get a list of all delegators of an address using TzScan API v3?
I have an issue trying to use javascript to get the circulating supply by requesting data from Tzscan API :
HTML code to request the circulating supply :
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width">
<title>JS Bin</title>
</head>
<body>
<h1>There Tezos Circulating : </h1>
<div id="getapi"></div>
</body>
</html>
Javascript Code to get the data from the API :
<script>
function createNode(element) {
return document.createElement(element);
}
function append(parent, el) {
return parent.appendChild(el);
}
const ul = document.getElementById('getapi');
const url = 'http://api6.tzscan.io/v3/supply';
fetch(url)
.then((resp) => resp.json())
.then(function(data) {
let span = createNode('span');
span.innerHTML = `${data.circulating_supply/1000000}`;
append(ul, span);
})
.catch(function(error) {
console.log(error);
});
</script>
The problem is that somehow it works when I create a HTML file locally but not online :
https://codepen.io/anon/pen/LaqqpB
api javascript circulating-supply
edited 4 mins ago
Frank
1,117317
asked 5 hours ago
LexxorLexxor
83
New contributor
Lexxor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
I have an issue trying to use javascript to get the circulating supply by requesting data from Tzscan API :
HTML code to request the circulating supply :
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width">
<title>JS Bin</title>
</head>
<body>
<h1>There Tezos Circulating : </h1>
<div id="getapi"></div>
</body>
</html>
Javascript Code to get the data from the API :
<script>
function createNode(element) {
return document.createElement(element);
}
function append(parent, el) {
return parent.appendChild(el);
}
const ul = document.getElementById('getapi');
const url = 'http://api6.tzscan.io/v3/supply';
fetch(url)
.then((resp) => resp.json())
.then(function(data) {
let span = createNode('span');
span.innerHTML = `${data.circulating_supply/1000000}`;
append(ul, span);
})
.catch(function(error) {
console.log(error);
});
</script>
The problem is that somehow it works when I create a HTML file locally but not online :
https://codepen.io/anon/pen/LaqqpB
api javascript circulating-supply
edited 4 mins ago
Frank
1,117317
asked 5 hours ago
LexxorLexxor
83
New contributor
Lexxor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
it'll help to also include the errors you are getting. I know we could probably look at your codepen but for the sake of the question, it's best include the errors in the question.
– Frank
2 mins ago
add a comment |
I have an issue trying to use javascript to get the circulating supply by requesting data from Tzscan API :
HTML code to request the circulating supply :
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width">
<title>JS Bin</title>
</head>
<body>
<h1>There Tezos Circulating : </h1>
<div id="getapi"></div>
</body>
</html>
Javascript Code to get the data from the API :
<script>
function createNode(element) {
return document.createElement(element);
}
function append(parent, el) {
return parent.appendChild(el);
}
const ul = document.getElementById('getapi');
const url = 'http://api6.tzscan.io/v3/supply';
fetch(url)
.then((resp) => resp.json())
.then(function(data) {
let span = createNode('span');
span.innerHTML = `${data.circulating_supply/1000000}`;
append(ul, span);
})
.catch(function(error) {
console.log(error);
});
</script>
The problem is that somehow it works when I create a HTML file locally but not online :
https://codepen.io/anon/pen/LaqqpB
api javascript circulating-supply
edited 4 mins ago
Frank
1,117317
asked 5 hours ago
LexxorLexxor
83
New contributor
Lexxor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I have an issue trying to use javascript to get the circulating supply by requesting data from Tzscan API :
HTML code to request the circulating supply :
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width">
<title>JS Bin</title>
</head>
<body>
<h1>There Tezos Circulating : </h1>
<div id="getapi"></div>
</body>
</html>
Javascript Code to get the data from the API :
<script>
function createNode(element) {
return document.createElement(element);
}
function append(parent, el) {
return parent.appendChild(el);
}
const ul = document.getElementById('getapi');
const url = 'http://api6.tzscan.io/v3/supply';
fetch(url)
.then((resp) => resp.json())
.then(function(data) {
let span = createNode('span');
span.innerHTML = `${data.circulating_supply/1000000}`;
append(ul, span);
})
.catch(function(error) {
console.log(error);
});
</script>
The problem is that somehow it works when I create a HTML file locally but not online :
https://codepen.io/anon/pen/LaqqpB
api javascript circulating-supply
api javascript circulating-supply
edited 4 mins ago
Frank
1,117317
asked 5 hours ago
LexxorLexxor
83
New contributor
Lexxor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 4 mins ago
Frank
1,117317
asked 5 hours ago
LexxorLexxor
83
New contributor
Lexxor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 4 mins ago
Frank
1,117317
edited 4 mins ago
Frank
1,117317
edited 4 mins ago
Frank
1,117317
1,117317
asked 5 hours ago
LexxorLexxor
83
New contributor
Lexxor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 5 hours ago
LexxorLexxor
83
asked 5 hours ago
LexxorLexxor
83
83
New contributor
Lexxor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Lexxor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Lexxor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
it'll help to also include the errors you are getting. I know we could probably look at your codepen but for the sake of the question, it's best include the errors in the question.
– Frank
2 mins ago
add a comment |
it'll help to also include the errors you are getting. I know we could probably look at your codepen but for the sake of the question, it's best include the errors in the question.
– Frank
2 mins ago
it'll help to also include the errors you are getting. I know we could probably look at your codepen but for the sake of the question, it's best include the errors in the question.
– Frank
2 mins ago
it'll help to also include the errors you are getting. I know we could probably look at your codepen but for the sake of the question, it's best include the errors in the question.
– Frank
2 mins ago
add a comment |
2 Answers
2
active
oldest
votes
You've encountered a mixed content error. Requests can't be a mixture of http and https, they need to be all of the same, preferably https. Just change the const url = 'http://api6.tzscan.io/v3/supply'; to be https
const url = 'https://api6.tzscan.io/v3/supply';
fetch(url)
.then(resp => resp.json())
.then(({dls}) => {
let span = createNode('span');
span.innerHTML = dls;
append(ul, span);
})
.catch(console.log);
answered 4 hours ago
Richard AyotteRichard Ayotte
16416
add a comment |
OMG, it works perfectly.
Thank you a lot.
answered 3 hours ago
LexxorLexxor
83
New contributor
Lexxor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
You're welcome. Better to mark the correct answer and just put comments under it instead of creating new answers to comment.
– Richard Ayotte
1 hour ago
Please don't add "thank you" as an answer. Instead, accept the answer that you found most helpful. - From Review
– Tom
58 mins ago
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
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oldest
votes
active
oldest
votes
You've encountered a mixed content error. Requests can't be a mixture of http and https, they need to be all of the same, preferably https. Just change the const url = 'http://api6.tzscan.io/v3/supply'; to be https
const url = 'https://api6.tzscan.io/v3/supply';
fetch(url)
.then(resp => resp.json())
.then(({dls}) => {
let span = createNode('span');
span.innerHTML = dls;
append(ul, span);
})
.catch(console.log);
answered 4 hours ago
Richard AyotteRichard Ayotte
16416
add a comment |
You've encountered a mixed content error. Requests can't be a mixture of http and https, they need to be all of the same, preferably https. Just change the const url = 'http://api6.tzscan.io/v3/supply'; to be https
const url = 'https://api6.tzscan.io/v3/supply';
fetch(url)
.then(resp => resp.json())
.then(({dls}) => {
let span = createNode('span');
span.innerHTML = dls;
append(ul, span);
})
.catch(console.log);
answered 4 hours ago
Richard AyotteRichard Ayotte
16416
add a comment |
You've encountered a mixed content error. Requests can't be a mixture of http and https, they need to be all of the same, preferably https. Just change the const url = 'http://api6.tzscan.io/v3/supply'; to be https
const url = 'https://api6.tzscan.io/v3/supply';
fetch(url)
.then(resp => resp.json())
.then(({dls}) => {
let span = createNode('span');
span.innerHTML = dls;
append(ul, span);
})
.catch(console.log);
answered 4 hours ago
Richard AyotteRichard Ayotte
16416
You've encountered a mixed content error. Requests can't be a mixture of http and https, they need to be all of the same, preferably https. Just change the const url = 'http://api6.tzscan.io/v3/supply'; to be https
const url = 'https://api6.tzscan.io/v3/supply';
fetch(url)
.then(resp => resp.json())
.then(({dls}) => {
let span = createNode('span');
span.innerHTML = dls;
append(ul, span);
})
.catch(console.log);
answered 4 hours ago
Richard AyotteRichard Ayotte
16416
edited 1 hour ago
answered 4 hours ago
Richard AyotteRichard Ayotte
16416
answered 4 hours ago
Richard AyotteRichard Ayotte
16416
answered 4 hours ago
Richard AyotteRichard Ayotte
16416
16416
add a comment |
add a comment |
OMG, it works perfectly.
Thank you a lot.
answered 3 hours ago
LexxorLexxor
83
New contributor
Lexxor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
You're welcome. Better to mark the correct answer and just put comments under it instead of creating new answers to comment.
– Richard Ayotte
1 hour ago
Please don't add "thank you" as an answer. Instead, accept the answer that you found most helpful. - From Review
– Tom
58 mins ago
add a comment |
OMG, it works perfectly.
Thank you a lot.
answered 3 hours ago
LexxorLexxor
83
New contributor
Lexxor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
You're welcome. Better to mark the correct answer and just put comments under it instead of creating new answers to comment.
– Richard Ayotte
1 hour ago
Please don't add "thank you" as an answer. Instead, accept the answer that you found most helpful. - From Review
– Tom
58 mins ago
add a comment |
OMG, it works perfectly.
Thank you a lot.
answered 3 hours ago
LexxorLexxor
83
New contributor
Lexxor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
OMG, it works perfectly.
Thank you a lot.
answered 3 hours ago
LexxorLexxor
83
New contributor
Lexxor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 3 hours ago
LexxorLexxor
83
New contributor
Lexxor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 3 hours ago
LexxorLexxor
83
answered 3 hours ago
LexxorLexxor
83
83
New contributor
Lexxor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Lexxor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Lexxor is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
You're welcome. Better to mark the correct answer and just put comments under it instead of creating new answers to comment.
– Richard Ayotte
1 hour ago
Please don't add "thank you" as an answer. Instead, accept the answer that you found most helpful. - From Review
– Tom
58 mins ago
add a comment |
You're welcome. Better to mark the correct answer and just put comments under it instead of creating new answers to comment.
– Richard Ayotte
1 hour ago
Please don't add "thank you" as an answer. Instead, accept the answer that you found most helpful. - From Review
– Tom
58 mins ago
You're welcome. Better to mark the correct answer and just put comments under it instead of creating new answers to comment.
– Richard Ayotte
1 hour ago
You're welcome. Better to mark the correct answer and just put comments under it instead of creating new answers to comment.
– Richard Ayotte
1 hour ago
Please don't add "thank you" as an answer. Instead, accept the answer that you found most helpful. - From Review
– Tom
58 mins ago
Please don't add "thank you" as an answer. Instead, accept the answer that you found most helpful. - From Review
– Tom
58 mins ago
add a comment |
Lexxor is a new contributor. Be nice, and check out our Code of Conduct.
Lexxor is a new contributor. Be nice, and check out our Code of Conduct.
Lexxor is a new contributor. Be nice, and check out our Code of Conduct.
Lexxor is a new contributor. Be nice, and check out our Code of Conduct.
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it'll help to also include the errors you are getting. I know we could probably look at your codepen but for the sake of the question, it's best include the errors in the question.
– Frank
2 mins ago