Combing two queries in oneSQL Select taking too much time to executeOne query two MySQL serversAre these two...
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Combing two queries in one
SQL Select taking too much time to executeOne query two MySQL serversAre these two queries logically equivalent?Combine multiple similar queries into oneAccess (Jet) SQL: DateTime stamps in TableB flanking each DateTime stamp in TableAQuery with two LEFT JOIN's is not working as expectedGenerating two rows from one source rowSubtract from two MYSQL QueriesFinding gaps on intersection datesHow to improve query performance through denormalization of this schema or other techniques?
I have two tables, e.g. "Locations" and "Connections"
"Locations" has values
Id | Dimension
---------------
1 | 4
2 | 8
3 | 2
"Connections" maintains attributes
Origin | Destination | Value | Distance_KM
-------------------------------------------
1 | 2 | 500 | 30
1 | 3 | 100 | 20
2 | 1 | 100 | 10
2 | 3 | 300 | 10
3 | 1 | 100 | 40
I want to create an output with the following Attribute Table. Where "In" correspond to "Destination" from "Connections" and "Out" to "Origin" accordingly.
Id | Dimension | In_Value | In_Count | In_Dist | Out_Value | Out_Count | Out_Dist
----------------------------------------------------------------------------------
1 | 4 | 200 | 2 | 50 | 600 | 2 | 50
2 | 8 | 500 | 1 | 30 | 400 | 2 | 20
3 | 2 | 400 | 2 | 30 | 100 | 1 | 40
I can achieve the result that I strive for separately with two queries.
Query 1
SELECT C.Destination, SUM(C.Value) AS In_Value, COUNT(C.Destination) AS In_Count, SUM(C.Distance_KM) AS In_Dist
FROM Connections AS C
GROUP BY C.Destination
Query 2
SELECT C.Origin, SUM(C.Value) AS Out_Value, COUNT(C.Origin) AS Out_Count, SUM(C.Origine_KM) AS Out_Dist
FROM Connections AS C
GROUP BY C.Origin
Nevertheless, there should be only one query that solves my issue, is not it? I tried this but no success.
SELECT L.Id AS Id, L.Dimension AS Dimension, C.In_Value, C.In_Count, C.In_Dist, C.Out_Value, C.Out_Count, C.Out_Dist
FROM Locations AS L
LEFT JOIN (
SELECT C.Destination, SUM(C.Value) AS In_Value, COUNT(C.Destination) AS In_Count, SUM(C.Distance_KM) AS In_Dist
FROM Connections AS C
GROUP BY C.Destination
) ON L.Id = C.Destination
LEFT JOIN (
SELECT C.Origin, SUM(C.Value) AS Out_Value, COUNT(C.Origin) AS Out_Count, SUM(C.Origine_KM) AS Out_Dist
FROM Connections AS C
GROUP BY C.Origin
) ON L.Id = C.Origin
Basically, I do not know if I eligible to add a second LEFT JOIN ON to the query with already existing LEFT JOIN ON, am I?
References:
- Two SQL LEFT JOINS produce incorrect result
- Multiple left joins on multiple tables in one query
query aggregate table
asked 6 mins ago
TarasTaras
1011
New contributor
Taras is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
I have two tables, e.g. "Locations" and "Connections"
"Locations" has values
Id | Dimension
---------------
1 | 4
2 | 8
3 | 2
"Connections" maintains attributes
Origin | Destination | Value | Distance_KM
-------------------------------------------
1 | 2 | 500 | 30
1 | 3 | 100 | 20
2 | 1 | 100 | 10
2 | 3 | 300 | 10
3 | 1 | 100 | 40
I want to create an output with the following Attribute Table. Where "In" correspond to "Destination" from "Connections" and "Out" to "Origin" accordingly.
Id | Dimension | In_Value | In_Count | In_Dist | Out_Value | Out_Count | Out_Dist
----------------------------------------------------------------------------------
1 | 4 | 200 | 2 | 50 | 600 | 2 | 50
2 | 8 | 500 | 1 | 30 | 400 | 2 | 20
3 | 2 | 400 | 2 | 30 | 100 | 1 | 40
I can achieve the result that I strive for separately with two queries.
Query 1
SELECT C.Destination, SUM(C.Value) AS In_Value, COUNT(C.Destination) AS In_Count, SUM(C.Distance_KM) AS In_Dist
FROM Connections AS C
GROUP BY C.Destination
Query 2
SELECT C.Origin, SUM(C.Value) AS Out_Value, COUNT(C.Origin) AS Out_Count, SUM(C.Origine_KM) AS Out_Dist
FROM Connections AS C
GROUP BY C.Origin
Nevertheless, there should be only one query that solves my issue, is not it? I tried this but no success.
SELECT L.Id AS Id, L.Dimension AS Dimension, C.In_Value, C.In_Count, C.In_Dist, C.Out_Value, C.Out_Count, C.Out_Dist
FROM Locations AS L
LEFT JOIN (
SELECT C.Destination, SUM(C.Value) AS In_Value, COUNT(C.Destination) AS In_Count, SUM(C.Distance_KM) AS In_Dist
FROM Connections AS C
GROUP BY C.Destination
) ON L.Id = C.Destination
LEFT JOIN (
SELECT C.Origin, SUM(C.Value) AS Out_Value, COUNT(C.Origin) AS Out_Count, SUM(C.Origine_KM) AS Out_Dist
FROM Connections AS C
GROUP BY C.Origin
) ON L.Id = C.Origin
Basically, I do not know if I eligible to add a second LEFT JOIN ON to the query with already existing LEFT JOIN ON, am I?
References:
- Two SQL LEFT JOINS produce incorrect result
- Multiple left joins on multiple tables in one query
query aggregate table
asked 6 mins ago
TarasTaras
1011
New contributor
Taras is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
I have two tables, e.g. "Locations" and "Connections"
"Locations" has values
Id | Dimension
---------------
1 | 4
2 | 8
3 | 2
"Connections" maintains attributes
Origin | Destination | Value | Distance_KM
-------------------------------------------
1 | 2 | 500 | 30
1 | 3 | 100 | 20
2 | 1 | 100 | 10
2 | 3 | 300 | 10
3 | 1 | 100 | 40
I want to create an output with the following Attribute Table. Where "In" correspond to "Destination" from "Connections" and "Out" to "Origin" accordingly.
Id | Dimension | In_Value | In_Count | In_Dist | Out_Value | Out_Count | Out_Dist
----------------------------------------------------------------------------------
1 | 4 | 200 | 2 | 50 | 600 | 2 | 50
2 | 8 | 500 | 1 | 30 | 400 | 2 | 20
3 | 2 | 400 | 2 | 30 | 100 | 1 | 40
I can achieve the result that I strive for separately with two queries.
Query 1
SELECT C.Destination, SUM(C.Value) AS In_Value, COUNT(C.Destination) AS In_Count, SUM(C.Distance_KM) AS In_Dist
FROM Connections AS C
GROUP BY C.Destination
Query 2
SELECT C.Origin, SUM(C.Value) AS Out_Value, COUNT(C.Origin) AS Out_Count, SUM(C.Origine_KM) AS Out_Dist
FROM Connections AS C
GROUP BY C.Origin
Nevertheless, there should be only one query that solves my issue, is not it? I tried this but no success.
SELECT L.Id AS Id, L.Dimension AS Dimension, C.In_Value, C.In_Count, C.In_Dist, C.Out_Value, C.Out_Count, C.Out_Dist
FROM Locations AS L
LEFT JOIN (
SELECT C.Destination, SUM(C.Value) AS In_Value, COUNT(C.Destination) AS In_Count, SUM(C.Distance_KM) AS In_Dist
FROM Connections AS C
GROUP BY C.Destination
) ON L.Id = C.Destination
LEFT JOIN (
SELECT C.Origin, SUM(C.Value) AS Out_Value, COUNT(C.Origin) AS Out_Count, SUM(C.Origine_KM) AS Out_Dist
FROM Connections AS C
GROUP BY C.Origin
) ON L.Id = C.Origin
Basically, I do not know if I eligible to add a second LEFT JOIN ON to the query with already existing LEFT JOIN ON, am I?
References:
- Two SQL LEFT JOINS produce incorrect result
- Multiple left joins on multiple tables in one query
query aggregate table
asked 6 mins ago
TarasTaras
1011
New contributor
Taras is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I have two tables, e.g. "Locations" and "Connections"
"Locations" has values
Id | Dimension
---------------
1 | 4
2 | 8
3 | 2
"Connections" maintains attributes
Origin | Destination | Value | Distance_KM
-------------------------------------------
1 | 2 | 500 | 30
1 | 3 | 100 | 20
2 | 1 | 100 | 10
2 | 3 | 300 | 10
3 | 1 | 100 | 40
I want to create an output with the following Attribute Table. Where "In" correspond to "Destination" from "Connections" and "Out" to "Origin" accordingly.
Id | Dimension | In_Value | In_Count | In_Dist | Out_Value | Out_Count | Out_Dist
----------------------------------------------------------------------------------
1 | 4 | 200 | 2 | 50 | 600 | 2 | 50
2 | 8 | 500 | 1 | 30 | 400 | 2 | 20
3 | 2 | 400 | 2 | 30 | 100 | 1 | 40
I can achieve the result that I strive for separately with two queries.
Query 1
SELECT C.Destination, SUM(C.Value) AS In_Value, COUNT(C.Destination) AS In_Count, SUM(C.Distance_KM) AS In_Dist
FROM Connections AS C
GROUP BY C.Destination
Query 2
SELECT C.Origin, SUM(C.Value) AS Out_Value, COUNT(C.Origin) AS Out_Count, SUM(C.Origine_KM) AS Out_Dist
FROM Connections AS C
GROUP BY C.Origin
Nevertheless, there should be only one query that solves my issue, is not it? I tried this but no success.
SELECT L.Id AS Id, L.Dimension AS Dimension, C.In_Value, C.In_Count, C.In_Dist, C.Out_Value, C.Out_Count, C.Out_Dist
FROM Locations AS L
LEFT JOIN (
SELECT C.Destination, SUM(C.Value) AS In_Value, COUNT(C.Destination) AS In_Count, SUM(C.Distance_KM) AS In_Dist
FROM Connections AS C
GROUP BY C.Destination
) ON L.Id = C.Destination
LEFT JOIN (
SELECT C.Origin, SUM(C.Value) AS Out_Value, COUNT(C.Origin) AS Out_Count, SUM(C.Origine_KM) AS Out_Dist
FROM Connections AS C
GROUP BY C.Origin
) ON L.Id = C.Origin
Basically, I do not know if I eligible to add a second LEFT JOIN ON to the query with already existing LEFT JOIN ON, am I?
References:
- Two SQL LEFT JOINS produce incorrect result
- Multiple left joins on multiple tables in one query
query aggregate table
query aggregate table
asked 6 mins ago
TarasTaras
1011
New contributor
Taras is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 6 mins ago
TarasTaras
1011
New contributor
Taras is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 31 secs ago
Taras
asked 6 mins ago
TarasTaras
1011
New contributor
Taras is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 6 mins ago
TarasTaras
1011
asked 6 mins ago
TarasTaras
1011
1011
New contributor
Taras is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Taras is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Taras is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
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