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Add number in the string after each letter
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I have several strings with a fixed format.
The format is one letter followed by a number, e.g., A3B1C7D1.
However, if the number behind a letter is 1, the string is written as A3BC7D.
What I want to do is to insert number 1, and convert the string from A3BC7D to A3B1C7D1.
My example data is
strings <- c("A", "A3BC3", "A2B1C")
What I want to get is:
strings_new <- c("A1", "A3B1C3", "A2B1C1")
Thanks a lot!
r regex string
edited 2 hours ago
markus
13.1k1234
asked 2 hours ago
DongDong
1466
add a comment |
I have several strings with a fixed format.
The format is one letter followed by a number, e.g., A3B1C7D1.
However, if the number behind a letter is 1, the string is written as A3BC7D.
What I want to do is to insert number 1, and convert the string from A3BC7D to A3B1C7D1.
My example data is
strings <- c("A", "A3BC3", "A2B1C")
What I want to get is:
strings_new <- c("A1", "A3B1C3", "A2B1C1")
Thanks a lot!
r regex string
edited 2 hours ago
markus
13.1k1234
asked 2 hours ago
DongDong
1466
add a comment |
I have several strings with a fixed format.
The format is one letter followed by a number, e.g., A3B1C7D1.
However, if the number behind a letter is 1, the string is written as A3BC7D.
What I want to do is to insert number 1, and convert the string from A3BC7D to A3B1C7D1.
My example data is
strings <- c("A", "A3BC3", "A2B1C")
What I want to get is:
strings_new <- c("A1", "A3B1C3", "A2B1C1")
Thanks a lot!
r regex string
edited 2 hours ago
markus
13.1k1234
asked 2 hours ago
DongDong
1466
I have several strings with a fixed format.
The format is one letter followed by a number, e.g., A3B1C7D1.
However, if the number behind a letter is 1, the string is written as A3BC7D.
What I want to do is to insert number 1, and convert the string from A3BC7D to A3B1C7D1.
My example data is
strings <- c("A", "A3BC3", "A2B1C")
What I want to get is:
strings_new <- c("A1", "A3B1C3", "A2B1C1")
Thanks a lot!
r regex string
r regex string
edited 2 hours ago
markus
13.1k1234
asked 2 hours ago
DongDong
1466
edited 2 hours ago
markus
13.1k1234
asked 2 hours ago
DongDong
1466
edited 2 hours ago
markus
13.1k1234
edited 2 hours ago
markus
13.1k1234
edited 2 hours ago
markus
13.1k1234
13.1k1234
asked 2 hours ago
DongDong
1466
asked 2 hours ago
DongDong
1466
asked 2 hours ago
DongDong
1466
1466
add a comment |
add a comment |
4 Answers
4
active
oldest
votes
Another option:
gsub("([A-Za-z])(?=[A-Za-z])|([A-Za-z])$", "\1\21", strings, perl = T)
Output:
[1] "A1" "A3B1C3" "A2B1C1"
Or if you only have capitals, just:
gsub("([A-Z])(?=[A-Z])|([A-Z])$", "\1\21", strings, perl = T)
Basically this finds letters that are either followed by another letter or are at the end of string, and replaces them with themselves while at the same time adds the desired number, 1 in this case.
answered 2 hours ago
arg0nautarg0naut
4,1191315
add a comment |
IIUC you could do:
gsub("(\D)(\D|$)", "\11\2", strings)
#[1] "A1" "A3B1C3" "A2B1C1"
We create two capture groups, the first is a signle non-digit (\D), the second is either a single non-digit or the end of the string (\D|$). Whenever there's a match in a string, this means two letters (non-digits) follow each other without a number in between. Hence, we use the replacement \11\2 to replace it with group1, then a 1, then group2 (which can also be the end of the string).
answered 2 hours ago
docendo discimusdocendo discimus
51.9k1179117
If I rungsub("(\D)(\D|$)", "\11\2", "AB"), I gotA1B
– Dong
1 min ago
add a comment |
Find all (uppercase) letters ([A-Z]) that is not followed by a number and replace it with that string + 1:
gsub("([A-Z])(?![0-9])", "\11", strings, perl = TRUE)
# [1] "A1" "A3B1C3" "A2B1C1"
answered 28 mins ago
sindri_baldursindri_baldur
7,7941032
add a comment |
strings[!grepl("[0-9]$",strings)]=paste0(strings[!grepl("[0-9]$",strings)],"1")
[1] "A1" "A3BC3" "A2B1C1"
We first grep all positions that do not end with a number, and paste a 1 to them.
answered 2 hours ago
boskiboski
490210
9
Almost. Check the second element it should be"A3B1C3"
– markus
2 hours ago
add a comment |
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
Another option:
gsub("([A-Za-z])(?=[A-Za-z])|([A-Za-z])$", "\1\21", strings, perl = T)
Output:
[1] "A1" "A3B1C3" "A2B1C1"
Or if you only have capitals, just:
gsub("([A-Z])(?=[A-Z])|([A-Z])$", "\1\21", strings, perl = T)
Basically this finds letters that are either followed by another letter or are at the end of string, and replaces them with themselves while at the same time adds the desired number, 1 in this case.
answered 2 hours ago
arg0nautarg0naut
4,1191315
add a comment |
Another option:
gsub("([A-Za-z])(?=[A-Za-z])|([A-Za-z])$", "\1\21", strings, perl = T)
Output:
[1] "A1" "A3B1C3" "A2B1C1"
Or if you only have capitals, just:
gsub("([A-Z])(?=[A-Z])|([A-Z])$", "\1\21", strings, perl = T)
Basically this finds letters that are either followed by another letter or are at the end of string, and replaces them with themselves while at the same time adds the desired number, 1 in this case.
answered 2 hours ago
arg0nautarg0naut
4,1191315
add a comment |
Another option:
gsub("([A-Za-z])(?=[A-Za-z])|([A-Za-z])$", "\1\21", strings, perl = T)
Output:
[1] "A1" "A3B1C3" "A2B1C1"
Or if you only have capitals, just:
gsub("([A-Z])(?=[A-Z])|([A-Z])$", "\1\21", strings, perl = T)
Basically this finds letters that are either followed by another letter or are at the end of string, and replaces them with themselves while at the same time adds the desired number, 1 in this case.
answered 2 hours ago
arg0nautarg0naut
4,1191315
Another option:
gsub("([A-Za-z])(?=[A-Za-z])|([A-Za-z])$", "\1\21", strings, perl = T)
Output:
[1] "A1" "A3B1C3" "A2B1C1"
Or if you only have capitals, just:
gsub("([A-Z])(?=[A-Z])|([A-Z])$", "\1\21", strings, perl = T)
Basically this finds letters that are either followed by another letter or are at the end of string, and replaces them with themselves while at the same time adds the desired number, 1 in this case.
answered 2 hours ago
arg0nautarg0naut
4,1191315
edited 2 hours ago
answered 2 hours ago
arg0nautarg0naut
4,1191315
answered 2 hours ago
arg0nautarg0naut
4,1191315
answered 2 hours ago
arg0nautarg0naut
4,1191315
4,1191315
add a comment |
add a comment |
IIUC you could do:
gsub("(\D)(\D|$)", "\11\2", strings)
#[1] "A1" "A3B1C3" "A2B1C1"
We create two capture groups, the first is a signle non-digit (\D), the second is either a single non-digit or the end of the string (\D|$). Whenever there's a match in a string, this means two letters (non-digits) follow each other without a number in between. Hence, we use the replacement \11\2 to replace it with group1, then a 1, then group2 (which can also be the end of the string).
answered 2 hours ago
docendo discimusdocendo discimus
51.9k1179117
If I rungsub("(\D)(\D|$)", "\11\2", "AB"), I gotA1B
– Dong
1 min ago
add a comment |
IIUC you could do:
gsub("(\D)(\D|$)", "\11\2", strings)
#[1] "A1" "A3B1C3" "A2B1C1"
We create two capture groups, the first is a signle non-digit (\D), the second is either a single non-digit or the end of the string (\D|$). Whenever there's a match in a string, this means two letters (non-digits) follow each other without a number in between. Hence, we use the replacement \11\2 to replace it with group1, then a 1, then group2 (which can also be the end of the string).
answered 2 hours ago
docendo discimusdocendo discimus
51.9k1179117
If I rungsub("(\D)(\D|$)", "\11\2", "AB"), I gotA1B
– Dong
1 min ago
add a comment |
IIUC you could do:
gsub("(\D)(\D|$)", "\11\2", strings)
#[1] "A1" "A3B1C3" "A2B1C1"
We create two capture groups, the first is a signle non-digit (\D), the second is either a single non-digit or the end of the string (\D|$). Whenever there's a match in a string, this means two letters (non-digits) follow each other without a number in between. Hence, we use the replacement \11\2 to replace it with group1, then a 1, then group2 (which can also be the end of the string).
answered 2 hours ago
docendo discimusdocendo discimus
51.9k1179117
IIUC you could do:
gsub("(\D)(\D|$)", "\11\2", strings)
#[1] "A1" "A3B1C3" "A2B1C1"
We create two capture groups, the first is a signle non-digit (\D), the second is either a single non-digit or the end of the string (\D|$). Whenever there's a match in a string, this means two letters (non-digits) follow each other without a number in between. Hence, we use the replacement \11\2 to replace it with group1, then a 1, then group2 (which can also be the end of the string).
answered 2 hours ago
docendo discimusdocendo discimus
51.9k1179117
edited 2 hours ago
answered 2 hours ago
docendo discimusdocendo discimus
51.9k1179117
answered 2 hours ago
docendo discimusdocendo discimus
51.9k1179117
answered 2 hours ago
docendo discimusdocendo discimus
51.9k1179117
51.9k1179117
If I rungsub("(\D)(\D|$)", "\11\2", "AB"), I gotA1B
– Dong
1 min ago
add a comment |
If I rungsub("(\D)(\D|$)", "\11\2", "AB"), I gotA1B
– Dong
1 min ago
If I run
gsub("(\D)(\D|$)", "\11\2", "AB"), I got A1B– Dong
1 min ago
If I run
gsub("(\D)(\D|$)", "\11\2", "AB"), I got A1B– Dong
1 min ago
add a comment |
Find all (uppercase) letters ([A-Z]) that is not followed by a number and replace it with that string + 1:
gsub("([A-Z])(?![0-9])", "\11", strings, perl = TRUE)
# [1] "A1" "A3B1C3" "A2B1C1"
answered 28 mins ago
sindri_baldursindri_baldur
7,7941032
add a comment |
Find all (uppercase) letters ([A-Z]) that is not followed by a number and replace it with that string + 1:
gsub("([A-Z])(?![0-9])", "\11", strings, perl = TRUE)
# [1] "A1" "A3B1C3" "A2B1C1"
answered 28 mins ago
sindri_baldursindri_baldur
7,7941032
add a comment |
Find all (uppercase) letters ([A-Z]) that is not followed by a number and replace it with that string + 1:
gsub("([A-Z])(?![0-9])", "\11", strings, perl = TRUE)
# [1] "A1" "A3B1C3" "A2B1C1"
answered 28 mins ago
sindri_baldursindri_baldur
7,7941032
Find all (uppercase) letters ([A-Z]) that is not followed by a number and replace it with that string + 1:
gsub("([A-Z])(?![0-9])", "\11", strings, perl = TRUE)
# [1] "A1" "A3B1C3" "A2B1C1"
answered 28 mins ago
sindri_baldursindri_baldur
7,7941032
edited 3 mins ago
answered 28 mins ago
sindri_baldursindri_baldur
7,7941032
answered 28 mins ago
sindri_baldursindri_baldur
7,7941032
answered 28 mins ago
sindri_baldursindri_baldur
7,7941032
7,7941032
add a comment |
add a comment |
strings[!grepl("[0-9]$",strings)]=paste0(strings[!grepl("[0-9]$",strings)],"1")
[1] "A1" "A3BC3" "A2B1C1"
We first grep all positions that do not end with a number, and paste a 1 to them.
answered 2 hours ago
boskiboski
490210
9
Almost. Check the second element it should be"A3B1C3"
– markus
2 hours ago
add a comment |
strings[!grepl("[0-9]$",strings)]=paste0(strings[!grepl("[0-9]$",strings)],"1")
[1] "A1" "A3BC3" "A2B1C1"
We first grep all positions that do not end with a number, and paste a 1 to them.
answered 2 hours ago
boskiboski
490210
9
Almost. Check the second element it should be"A3B1C3"
– markus
2 hours ago
add a comment |
strings[!grepl("[0-9]$",strings)]=paste0(strings[!grepl("[0-9]$",strings)],"1")
[1] "A1" "A3BC3" "A2B1C1"
We first grep all positions that do not end with a number, and paste a 1 to them.
answered 2 hours ago
boskiboski
490210
strings[!grepl("[0-9]$",strings)]=paste0(strings[!grepl("[0-9]$",strings)],"1")
[1] "A1" "A3BC3" "A2B1C1"
We first grep all positions that do not end with a number, and paste a 1 to them.
answered 2 hours ago
boskiboski
490210
answered 2 hours ago
boskiboski
490210
answered 2 hours ago
boskiboski
490210
answered 2 hours ago
boskiboski
490210
490210
9
Almost. Check the second element it should be"A3B1C3"
– markus
2 hours ago
add a comment |
9
Almost. Check the second element it should be"A3B1C3"
– markus
2 hours ago
9
9
Almost. Check the second element it should be
"A3B1C3"– markus
2 hours ago
Almost. Check the second element it should be
"A3B1C3"– markus
2 hours ago
add a comment |
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