ms sql query multiple table colums as identical tag (sequel)ms sql query multiple table colums as identical...

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ms sql query multiple table colums as identical tag (sequel)


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Extending this original question



I am using SQL Server Express 2017



Pretending this is my source table:



+-------------+---------------------------+
| ID | Name | Age | HairColor | HasCar |
+-------------+---------------------------+
| 1 | Bert | 25 | blonde | 1 |
| 2 | Agnes | 61 | white | 0 |
| 3 | Diane | 43 | brunette | 1 |
+-------------+---------------------------+


How can get a result looking like this?



<MyRootElement>
<MyGroupingTag Group="a">
<MyTag Value="1" />
<MyTag Value="Bert" />
<MyTag Value="25" />
<MyTag Value="blonde" />
<MyTag Value="1" />
</MyGroupingTag>
<MyGroupingTag Group="b">
<MyTag Value="2" />
<MyTag Value="Agnes" />
<MyTag Value="61" />
<MyTag Value="white" />
<MyTag Value="0" />
</MyGroupingTag>
<MyGroupingTag Group="c">
<MyTag Value="3" />
<MyTag Value="Diane" />
<MyTag Value="43" />
<MyTag Value="brunette" />
<MyTag Value="1" />
</MyGroupingTag>
</MyRootElement>


Because of the Group attribute in MyGroupingTag I can't use something like



SELECT... FOR XML PATH('MyTag'), ROOT('MyGroupingTag')









share







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GeorgeDuke is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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    -1















    Extending this original question



    I am using SQL Server Express 2017



    Pretending this is my source table:



    +-------------+---------------------------+
    | ID | Name | Age | HairColor | HasCar |
    +-------------+---------------------------+
    | 1 | Bert | 25 | blonde | 1 |
    | 2 | Agnes | 61 | white | 0 |
    | 3 | Diane | 43 | brunette | 1 |
    +-------------+---------------------------+


    How can get a result looking like this?



    <MyRootElement>
    <MyGroupingTag Group="a">
    <MyTag Value="1" />
    <MyTag Value="Bert" />
    <MyTag Value="25" />
    <MyTag Value="blonde" />
    <MyTag Value="1" />
    </MyGroupingTag>
    <MyGroupingTag Group="b">
    <MyTag Value="2" />
    <MyTag Value="Agnes" />
    <MyTag Value="61" />
    <MyTag Value="white" />
    <MyTag Value="0" />
    </MyGroupingTag>
    <MyGroupingTag Group="c">
    <MyTag Value="3" />
    <MyTag Value="Diane" />
    <MyTag Value="43" />
    <MyTag Value="brunette" />
    <MyTag Value="1" />
    </MyGroupingTag>
    </MyRootElement>


    Because of the Group attribute in MyGroupingTag I can't use something like



    SELECT... FOR XML PATH('MyTag'), ROOT('MyGroupingTag')









    share







    New contributor




    GeorgeDuke is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.























      -1












      -1








      -1








      Extending this original question



      I am using SQL Server Express 2017



      Pretending this is my source table:



      +-------------+---------------------------+
      | ID | Name | Age | HairColor | HasCar |
      +-------------+---------------------------+
      | 1 | Bert | 25 | blonde | 1 |
      | 2 | Agnes | 61 | white | 0 |
      | 3 | Diane | 43 | brunette | 1 |
      +-------------+---------------------------+


      How can get a result looking like this?



      <MyRootElement>
      <MyGroupingTag Group="a">
      <MyTag Value="1" />
      <MyTag Value="Bert" />
      <MyTag Value="25" />
      <MyTag Value="blonde" />
      <MyTag Value="1" />
      </MyGroupingTag>
      <MyGroupingTag Group="b">
      <MyTag Value="2" />
      <MyTag Value="Agnes" />
      <MyTag Value="61" />
      <MyTag Value="white" />
      <MyTag Value="0" />
      </MyGroupingTag>
      <MyGroupingTag Group="c">
      <MyTag Value="3" />
      <MyTag Value="Diane" />
      <MyTag Value="43" />
      <MyTag Value="brunette" />
      <MyTag Value="1" />
      </MyGroupingTag>
      </MyRootElement>


      Because of the Group attribute in MyGroupingTag I can't use something like



      SELECT... FOR XML PATH('MyTag'), ROOT('MyGroupingTag')









      share







      New contributor




      GeorgeDuke is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.












      Extending this original question



      I am using SQL Server Express 2017



      Pretending this is my source table:



      +-------------+---------------------------+
      | ID | Name | Age | HairColor | HasCar |
      +-------------+---------------------------+
      | 1 | Bert | 25 | blonde | 1 |
      | 2 | Agnes | 61 | white | 0 |
      | 3 | Diane | 43 | brunette | 1 |
      +-------------+---------------------------+


      How can get a result looking like this?



      <MyRootElement>
      <MyGroupingTag Group="a">
      <MyTag Value="1" />
      <MyTag Value="Bert" />
      <MyTag Value="25" />
      <MyTag Value="blonde" />
      <MyTag Value="1" />
      </MyGroupingTag>
      <MyGroupingTag Group="b">
      <MyTag Value="2" />
      <MyTag Value="Agnes" />
      <MyTag Value="61" />
      <MyTag Value="white" />
      <MyTag Value="0" />
      </MyGroupingTag>
      <MyGroupingTag Group="c">
      <MyTag Value="3" />
      <MyTag Value="Diane" />
      <MyTag Value="43" />
      <MyTag Value="brunette" />
      <MyTag Value="1" />
      </MyGroupingTag>
      </MyRootElement>


      Because of the Group attribute in MyGroupingTag I can't use something like



      SELECT... FOR XML PATH('MyTag'), ROOT('MyGroupingTag')







      sql-server xml





      share







      New contributor




      GeorgeDuke is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.










      share







      New contributor




      GeorgeDuke is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.








      share



      share






      New contributor




      GeorgeDuke is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      asked 8 mins ago









      GeorgeDukeGeorgeDuke

      12




      12




      New contributor




      GeorgeDuke is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      New contributor





      GeorgeDuke is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






      GeorgeDuke is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






















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