ms sql query multiple table colums as identical tag (sequel)ms sql query multiple table colums as identical...
Did Shadowfax go to Valinor?
Stopping power of mountain vs road bike
How can I fix/modify my tub/shower combo so the water comes out of the showerhead?
Assassin's bullet with mercury
What is a clear way to write a bar that has an extra beat?
Has there ever been an airliner design involving reducing generator load by installing solar panels?
Why does Kotter return in Welcome Back Kotter?
What mechanic is there to disable a threat instead of killing it?
How can I make my BBEG immortal short of making them a Lich or Vampire?
How much of data wrangling is a data scientist's job?
Today is the Center
A reference to a well-known characterization of scattered compact spaces
Intersection of two sorted vectors in C++
Infinite Abelian subgroup of infinite non Abelian group example
Does a druid starting with a bow start with no arrows?
How could indestructible materials be used in power generation?
Is it inappropriate for a student to attend their mentor's dissertation defense?
1960's book about a plague that kills all white people
Doing something right before you need it - expression for this?
Can I ask the recruiters in my resume to put the reason why I am rejected?
Would Slavery Reparations be considered Bills of Attainder and hence Illegal?
I'm flying to France today and my passport expires in less than 2 months
Were any external disk drives stacked vertically?
How to model explosives?
ms sql query multiple table colums as identical tag (sequel)
ms sql query multiple table colums as identical tagSelect XML values when attribute involvedHow to include concatenated values in a dynamic pivot column value?Parsing Typed XML with a default namespace and inconsistent root nodeHowto query xmlFull text search in XML documentsSQL Row concatenation with XML PATH and STUFF giving aggregate sql errorGet attribute value of XMLDistinct XML values mysqlINSERT/SELECT xml column from one table to anotherms sql query multiple table colums as identical tag
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ margin-bottom:0;
}
Extending this original question
I am using SQL Server Express 2017
Pretending this is my source table:
+-------------+---------------------------+
| ID | Name | Age | HairColor | HasCar |
+-------------+---------------------------+
| 1 | Bert | 25 | blonde | 1 |
| 2 | Agnes | 61 | white | 0 |
| 3 | Diane | 43 | brunette | 1 |
+-------------+---------------------------+
How can get a result looking like this?
<MyRootElement>
<MyGroupingTag Group="a">
<MyTag Value="1" />
<MyTag Value="Bert" />
<MyTag Value="25" />
<MyTag Value="blonde" />
<MyTag Value="1" />
</MyGroupingTag>
<MyGroupingTag Group="b">
<MyTag Value="2" />
<MyTag Value="Agnes" />
<MyTag Value="61" />
<MyTag Value="white" />
<MyTag Value="0" />
</MyGroupingTag>
<MyGroupingTag Group="c">
<MyTag Value="3" />
<MyTag Value="Diane" />
<MyTag Value="43" />
<MyTag Value="brunette" />
<MyTag Value="1" />
</MyGroupingTag>
</MyRootElement>
Because of the Group attribute in MyGroupingTag I can't use something like
SELECT... FOR XML PATH('MyTag'), ROOT('MyGroupingTag')
sql-server xml
New contributor
add a comment |
Extending this original question
I am using SQL Server Express 2017
Pretending this is my source table:
+-------------+---------------------------+
| ID | Name | Age | HairColor | HasCar |
+-------------+---------------------------+
| 1 | Bert | 25 | blonde | 1 |
| 2 | Agnes | 61 | white | 0 |
| 3 | Diane | 43 | brunette | 1 |
+-------------+---------------------------+
How can get a result looking like this?
<MyRootElement>
<MyGroupingTag Group="a">
<MyTag Value="1" />
<MyTag Value="Bert" />
<MyTag Value="25" />
<MyTag Value="blonde" />
<MyTag Value="1" />
</MyGroupingTag>
<MyGroupingTag Group="b">
<MyTag Value="2" />
<MyTag Value="Agnes" />
<MyTag Value="61" />
<MyTag Value="white" />
<MyTag Value="0" />
</MyGroupingTag>
<MyGroupingTag Group="c">
<MyTag Value="3" />
<MyTag Value="Diane" />
<MyTag Value="43" />
<MyTag Value="brunette" />
<MyTag Value="1" />
</MyGroupingTag>
</MyRootElement>
Because of the Group attribute in MyGroupingTag I can't use something like
SELECT... FOR XML PATH('MyTag'), ROOT('MyGroupingTag')
sql-server xml
New contributor
add a comment |
Extending this original question
I am using SQL Server Express 2017
Pretending this is my source table:
+-------------+---------------------------+
| ID | Name | Age | HairColor | HasCar |
+-------------+---------------------------+
| 1 | Bert | 25 | blonde | 1 |
| 2 | Agnes | 61 | white | 0 |
| 3 | Diane | 43 | brunette | 1 |
+-------------+---------------------------+
How can get a result looking like this?
<MyRootElement>
<MyGroupingTag Group="a">
<MyTag Value="1" />
<MyTag Value="Bert" />
<MyTag Value="25" />
<MyTag Value="blonde" />
<MyTag Value="1" />
</MyGroupingTag>
<MyGroupingTag Group="b">
<MyTag Value="2" />
<MyTag Value="Agnes" />
<MyTag Value="61" />
<MyTag Value="white" />
<MyTag Value="0" />
</MyGroupingTag>
<MyGroupingTag Group="c">
<MyTag Value="3" />
<MyTag Value="Diane" />
<MyTag Value="43" />
<MyTag Value="brunette" />
<MyTag Value="1" />
</MyGroupingTag>
</MyRootElement>
Because of the Group attribute in MyGroupingTag I can't use something like
SELECT... FOR XML PATH('MyTag'), ROOT('MyGroupingTag')
sql-server xml
New contributor
Extending this original question
I am using SQL Server Express 2017
Pretending this is my source table:
+-------------+---------------------------+
| ID | Name | Age | HairColor | HasCar |
+-------------+---------------------------+
| 1 | Bert | 25 | blonde | 1 |
| 2 | Agnes | 61 | white | 0 |
| 3 | Diane | 43 | brunette | 1 |
+-------------+---------------------------+
How can get a result looking like this?
<MyRootElement>
<MyGroupingTag Group="a">
<MyTag Value="1" />
<MyTag Value="Bert" />
<MyTag Value="25" />
<MyTag Value="blonde" />
<MyTag Value="1" />
</MyGroupingTag>
<MyGroupingTag Group="b">
<MyTag Value="2" />
<MyTag Value="Agnes" />
<MyTag Value="61" />
<MyTag Value="white" />
<MyTag Value="0" />
</MyGroupingTag>
<MyGroupingTag Group="c">
<MyTag Value="3" />
<MyTag Value="Diane" />
<MyTag Value="43" />
<MyTag Value="brunette" />
<MyTag Value="1" />
</MyGroupingTag>
</MyRootElement>
Because of the Group attribute in MyGroupingTag I can't use something like
SELECT... FOR XML PATH('MyTag'), ROOT('MyGroupingTag')
sql-server xml
sql-server xml
New contributor
New contributor
New contributor
asked 8 mins ago
GeorgeDukeGeorgeDuke
12
12
New contributor
New contributor
add a comment |
add a comment |
0
active
oldest
votes
Your Answer
StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "182"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});
function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});
}
});
GeorgeDuke is a new contributor. Be nice, and check out our Code of Conduct.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fdba.stackexchange.com%2fquestions%2f234011%2fms-sql-query-multiple-table-colums-as-identical-tag-sequel%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
0
active
oldest
votes
0
active
oldest
votes
active
oldest
votes
active
oldest
votes
GeorgeDuke is a new contributor. Be nice, and check out our Code of Conduct.
GeorgeDuke is a new contributor. Be nice, and check out our Code of Conduct.
GeorgeDuke is a new contributor. Be nice, and check out our Code of Conduct.
GeorgeDuke is a new contributor. Be nice, and check out our Code of Conduct.
Thanks for contributing an answer to Database Administrators Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fdba.stackexchange.com%2fquestions%2f234011%2fms-sql-query-multiple-table-colums-as-identical-tag-sequel%23new-answer', 'question_page');
}
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown