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Check if object is null and return null
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I'm doing a query to an object. My question is if nothing returns is it technically null. I want to return null if it is.
People person = [SELECT Id, Type FROM People WHERE (Type LIKE '%Construction%') limit 1];
if (person == null){
return null;
}
apex visualforce visualforce-component
asked 52 mins ago
ebarebar
132
add a comment |
I'm doing a query to an object. My question is if nothing returns is it technically null. I want to return null if it is.
People person = [SELECT Id, Type FROM People WHERE (Type LIKE '%Construction%') limit 1];
if (person == null){
return null;
}
apex visualforce visualforce-component
asked 52 mins ago
ebarebar
132
add a comment |
I'm doing a query to an object. My question is if nothing returns is it technically null. I want to return null if it is.
People person = [SELECT Id, Type FROM People WHERE (Type LIKE '%Construction%') limit 1];
if (person == null){
return null;
}
apex visualforce visualforce-component
asked 52 mins ago
ebarebar
132
I'm doing a query to an object. My question is if nothing returns is it technically null. I want to return null if it is.
People person = [SELECT Id, Type FROM People WHERE (Type LIKE '%Construction%') limit 1];
if (person == null){
return null;
}
apex visualforce visualforce-component
apex visualforce visualforce-component
asked 52 mins ago
ebarebar
132
asked 52 mins ago
ebarebar
132
asked 52 mins ago
ebarebar
132
asked 52 mins ago
ebarebar
132
asked 52 mins ago
ebarebar
132
132
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
One way to do this is to check for the number of records returned:
People[] persons = [...];
if (persons.size() == 0) return null;
as your code as written will generate this exception if no records match:
System.QueryException: List has no rows for assignment to SObject
answered 49 mins ago
Keith CKeith C
96.1k1094212
add a comment |
The syntax in your code throws a QueryException if you try it. Instead, use one of the other common patterns. This is one that I use:
People person; // is null
for(People record: [SELECT Type FROM People WHERE Type LIKE '%Construction%' LIMIT 1]) {
person = record;
}
return person; // will return null or a single record
answered 48 mins ago
sfdcfoxsfdcfox
260k12205450
The syntax in your code throws a QueryException if you try it -- only if there's no record returned.
– Jayant Das
18 mins ago
add a comment |
Change the code to:
People[] people = [SELECT Id, Type FROM People WHERE (Type LIKE '%Construction%') LIMIT 1];
if (people.size() == 0){
return null;
} else {
return people[0];
}
answered 48 mins ago
Phil WPhil W
471210
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
One way to do this is to check for the number of records returned:
People[] persons = [...];
if (persons.size() == 0) return null;
as your code as written will generate this exception if no records match:
System.QueryException: List has no rows for assignment to SObject
answered 49 mins ago
Keith CKeith C
96.1k1094212
add a comment |
One way to do this is to check for the number of records returned:
People[] persons = [...];
if (persons.size() == 0) return null;
as your code as written will generate this exception if no records match:
System.QueryException: List has no rows for assignment to SObject
answered 49 mins ago
Keith CKeith C
96.1k1094212
add a comment |
One way to do this is to check for the number of records returned:
People[] persons = [...];
if (persons.size() == 0) return null;
as your code as written will generate this exception if no records match:
System.QueryException: List has no rows for assignment to SObject
answered 49 mins ago
Keith CKeith C
96.1k1094212
One way to do this is to check for the number of records returned:
People[] persons = [...];
if (persons.size() == 0) return null;
as your code as written will generate this exception if no records match:
System.QueryException: List has no rows for assignment to SObject
answered 49 mins ago
Keith CKeith C
96.1k1094212
answered 49 mins ago
Keith CKeith C
96.1k1094212
answered 49 mins ago
Keith CKeith C
96.1k1094212
answered 49 mins ago
Keith CKeith C
96.1k1094212
96.1k1094212
add a comment |
add a comment |
The syntax in your code throws a QueryException if you try it. Instead, use one of the other common patterns. This is one that I use:
People person; // is null
for(People record: [SELECT Type FROM People WHERE Type LIKE '%Construction%' LIMIT 1]) {
person = record;
}
return person; // will return null or a single record
answered 48 mins ago
sfdcfoxsfdcfox
260k12205450
The syntax in your code throws a QueryException if you try it -- only if there's no record returned.
– Jayant Das
18 mins ago
add a comment |
The syntax in your code throws a QueryException if you try it. Instead, use one of the other common patterns. This is one that I use:
People person; // is null
for(People record: [SELECT Type FROM People WHERE Type LIKE '%Construction%' LIMIT 1]) {
person = record;
}
return person; // will return null or a single record
answered 48 mins ago
sfdcfoxsfdcfox
260k12205450
The syntax in your code throws a QueryException if you try it -- only if there's no record returned.
– Jayant Das
18 mins ago
add a comment |
The syntax in your code throws a QueryException if you try it. Instead, use one of the other common patterns. This is one that I use:
People person; // is null
for(People record: [SELECT Type FROM People WHERE Type LIKE '%Construction%' LIMIT 1]) {
person = record;
}
return person; // will return null or a single record
answered 48 mins ago
sfdcfoxsfdcfox
260k12205450
The syntax in your code throws a QueryException if you try it. Instead, use one of the other common patterns. This is one that I use:
People person; // is null
for(People record: [SELECT Type FROM People WHERE Type LIKE '%Construction%' LIMIT 1]) {
person = record;
}
return person; // will return null or a single record
answered 48 mins ago
sfdcfoxsfdcfox
260k12205450
answered 48 mins ago
sfdcfoxsfdcfox
260k12205450
answered 48 mins ago
sfdcfoxsfdcfox
260k12205450
answered 48 mins ago
sfdcfoxsfdcfox
260k12205450
260k12205450
The syntax in your code throws a QueryException if you try it -- only if there's no record returned.
– Jayant Das
18 mins ago
add a comment |
The syntax in your code throws a QueryException if you try it -- only if there's no record returned.
– Jayant Das
18 mins ago
The syntax in your code throws a QueryException if you try it -- only if there's no record returned.
– Jayant Das
18 mins ago
The syntax in your code throws a QueryException if you try it -- only if there's no record returned.
– Jayant Das
18 mins ago
add a comment |
Change the code to:
People[] people = [SELECT Id, Type FROM People WHERE (Type LIKE '%Construction%') LIMIT 1];
if (people.size() == 0){
return null;
} else {
return people[0];
}
answered 48 mins ago
Phil WPhil W
471210
add a comment |
Change the code to:
People[] people = [SELECT Id, Type FROM People WHERE (Type LIKE '%Construction%') LIMIT 1];
if (people.size() == 0){
return null;
} else {
return people[0];
}
answered 48 mins ago
Phil WPhil W
471210
add a comment |
Change the code to:
People[] people = [SELECT Id, Type FROM People WHERE (Type LIKE '%Construction%') LIMIT 1];
if (people.size() == 0){
return null;
} else {
return people[0];
}
answered 48 mins ago
Phil WPhil W
471210
Change the code to:
People[] people = [SELECT Id, Type FROM People WHERE (Type LIKE '%Construction%') LIMIT 1];
if (people.size() == 0){
return null;
} else {
return people[0];
}
answered 48 mins ago
Phil WPhil W
471210
answered 48 mins ago
Phil WPhil W
471210
answered 48 mins ago
Phil WPhil W
471210
answered 48 mins ago
Phil WPhil W
471210
471210
add a comment |
add a comment |
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