What is the smallest number n> 5 so that 5 ^ n ends with “3125”?How to prove that if $aequiv b...
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What is the smallest number n> 5 so that 5 ^ n ends with “3125”?
How to prove that if $aequiv b pmod{kn}$ then $a^kequiv b^k pmod{k^2n}$Horizontal tank with hemispherical ends depth to capacity calculationDoes the smallest real number that satisfies $2^xge bx$ have logarithmic order?Determine the smallest number POptimization, find the dimensions of the poster with the smallest areaIs $s(t) = 1/(1+t^2)$ a bounded function? If so, find the smallest $M$Continous function approximating the precision of a number.What is the smallest value of this sequence?Find the smallest real number $agt 0$ for which the equation $a^x=x$ has no real solutionsGiven a point A (3,4) What is the smallest segment passing through A and makes a right triangle with the coordinates$f(n) =$ the smallest prime factor of $n$. Prove that the number of solutions to the equation $f(x) = 2016$.
$begingroup$
What is the smallest number n> 5 so that 5 ^ n ends with "3125"?
What other examples are there?
calculus
New contributor
Catherine Cooper is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
What is the smallest number n> 5 so that 5 ^ n ends with "3125"?
What other examples are there?
calculus
New contributor
Catherine Cooper is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
1
$begingroup$
What is your take on this?
$endgroup$
– ADITYA PRAKASH
2 hours ago
1
$begingroup$
Why not just list them out and find it?
$endgroup$
– Jair Taylor
2 hours ago
3
$begingroup$
Why not just do it? It's not $1$ because $5^1=5$. It's not $2$ because $5^2 = 25$. What's to keep you from just continuing?
$endgroup$
– fleablood
1 hour ago
add a comment |
$begingroup$
What is the smallest number n> 5 so that 5 ^ n ends with "3125"?
What other examples are there?
calculus
New contributor
Catherine Cooper is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
What is the smallest number n> 5 so that 5 ^ n ends with "3125"?
What other examples are there?
calculus
calculus
New contributor
Catherine Cooper is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Catherine Cooper is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Catherine Cooper is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 2 hours ago
Catherine Cooper Catherine Cooper
291
291
New contributor
Catherine Cooper is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Catherine Cooper is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Catherine Cooper is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
1
$begingroup$
What is your take on this?
$endgroup$
– ADITYA PRAKASH
2 hours ago
1
$begingroup$
Why not just list them out and find it?
$endgroup$
– Jair Taylor
2 hours ago
3
$begingroup$
Why not just do it? It's not $1$ because $5^1=5$. It's not $2$ because $5^2 = 25$. What's to keep you from just continuing?
$endgroup$
– fleablood
1 hour ago
add a comment |
1
$begingroup$
What is your take on this?
$endgroup$
– ADITYA PRAKASH
2 hours ago
1
$begingroup$
Why not just list them out and find it?
$endgroup$
– Jair Taylor
2 hours ago
3
$begingroup$
Why not just do it? It's not $1$ because $5^1=5$. It's not $2$ because $5^2 = 25$. What's to keep you from just continuing?
$endgroup$
– fleablood
1 hour ago
1
1
$begingroup$
What is your take on this?
$endgroup$
– ADITYA PRAKASH
2 hours ago
$begingroup$
What is your take on this?
$endgroup$
– ADITYA PRAKASH
2 hours ago
1
1
$begingroup$
Why not just list them out and find it?
$endgroup$
– Jair Taylor
2 hours ago
$begingroup$
Why not just list them out and find it?
$endgroup$
– Jair Taylor
2 hours ago
3
3
$begingroup$
Why not just do it? It's not $1$ because $5^1=5$. It's not $2$ because $5^2 = 25$. What's to keep you from just continuing?
$endgroup$
– fleablood
1 hour ago
$begingroup$
Why not just do it? It's not $1$ because $5^1=5$. It's not $2$ because $5^2 = 25$. What's to keep you from just continuing?
$endgroup$
– fleablood
1 hour ago
add a comment |
4 Answers
4
active
oldest
votes
$begingroup$
So, we are looking for all $n>5$ for which $5^nequiv 3125=5^5mod 10000$.
Note that the following equivalence holds for $n>5$:$$5^nequiv 5^5mod 10000\iff \5^{n-4}equiv 5mod 16\iff\5^{n-5}equiv 1mod 16$$Define $mtriangleq n-5ge 1$. Then all the $m$s for which $5^{m}equiv 1mod 16$ holds are $$m=4kquad,quad kin Bbb N$$this is because $5^4=625equiv 1mod 16$ and therefore $$5^{4k}equiv5^{4k-4}equivcdots equiv 5^{4}equiv 1mod 16$$
Conclusion
All $n>5$s for which $5^n$ ends up with $3125$ can be found from $$n=4k+5quad,quad kin Bbb N$$ and the smallest such $n$ is 9.
$endgroup$
add a comment |
$begingroup$
Hint: $5^n equiv 5^5 mod 10^4$ if and only if $5^n equiv 5^5 mod 2^4$. What is the multiplicative order of $5$ mod $16$?
$endgroup$
add a comment |
$begingroup$
Well
$$5^9=1953125$$
so the answer is $9$. In fact
$$5^nequiv 5^{n-4} mod{10^4}$$
For $nge 8$, so any value of $5^{5+4k}$ where $kinmathbb{N}$ has the last four digits $3125$.
$endgroup$
$begingroup$
Why not $5^5 = 3125$.
$endgroup$
– fleablood
1 hour ago
1
$begingroup$
The question states that $ngt5$
$endgroup$
– Peter Foreman
1 hour ago
add a comment |
$begingroup$
Hint $ 5^{large 5+N}! bmod 10^{large 4} = 5^{large 5}(5^{largecolor{#c00} N}! bmod 2^{large 4}),,$ and $ 5^{largecolor{#c00} 4}equiv 1^{largecolor{#c00} 4}! pmod{!4^{large 2}},$ by $,5 equiv 1pmod{! color{#c00}4} $
$endgroup$
add a comment |
Your Answer
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
So, we are looking for all $n>5$ for which $5^nequiv 3125=5^5mod 10000$.
Note that the following equivalence holds for $n>5$:$$5^nequiv 5^5mod 10000\iff \5^{n-4}equiv 5mod 16\iff\5^{n-5}equiv 1mod 16$$Define $mtriangleq n-5ge 1$. Then all the $m$s for which $5^{m}equiv 1mod 16$ holds are $$m=4kquad,quad kin Bbb N$$this is because $5^4=625equiv 1mod 16$ and therefore $$5^{4k}equiv5^{4k-4}equivcdots equiv 5^{4}equiv 1mod 16$$
Conclusion
All $n>5$s for which $5^n$ ends up with $3125$ can be found from $$n=4k+5quad,quad kin Bbb N$$ and the smallest such $n$ is 9.
$endgroup$
add a comment |
$begingroup$
So, we are looking for all $n>5$ for which $5^nequiv 3125=5^5mod 10000$.
Note that the following equivalence holds for $n>5$:$$5^nequiv 5^5mod 10000\iff \5^{n-4}equiv 5mod 16\iff\5^{n-5}equiv 1mod 16$$Define $mtriangleq n-5ge 1$. Then all the $m$s for which $5^{m}equiv 1mod 16$ holds are $$m=4kquad,quad kin Bbb N$$this is because $5^4=625equiv 1mod 16$ and therefore $$5^{4k}equiv5^{4k-4}equivcdots equiv 5^{4}equiv 1mod 16$$
Conclusion
All $n>5$s for which $5^n$ ends up with $3125$ can be found from $$n=4k+5quad,quad kin Bbb N$$ and the smallest such $n$ is 9.
$endgroup$
add a comment |
$begingroup$
So, we are looking for all $n>5$ for which $5^nequiv 3125=5^5mod 10000$.
Note that the following equivalence holds for $n>5$:$$5^nequiv 5^5mod 10000\iff \5^{n-4}equiv 5mod 16\iff\5^{n-5}equiv 1mod 16$$Define $mtriangleq n-5ge 1$. Then all the $m$s for which $5^{m}equiv 1mod 16$ holds are $$m=4kquad,quad kin Bbb N$$this is because $5^4=625equiv 1mod 16$ and therefore $$5^{4k}equiv5^{4k-4}equivcdots equiv 5^{4}equiv 1mod 16$$
Conclusion
All $n>5$s for which $5^n$ ends up with $3125$ can be found from $$n=4k+5quad,quad kin Bbb N$$ and the smallest such $n$ is 9.
$endgroup$
So, we are looking for all $n>5$ for which $5^nequiv 3125=5^5mod 10000$.
Note that the following equivalence holds for $n>5$:$$5^nequiv 5^5mod 10000\iff \5^{n-4}equiv 5mod 16\iff\5^{n-5}equiv 1mod 16$$Define $mtriangleq n-5ge 1$. Then all the $m$s for which $5^{m}equiv 1mod 16$ holds are $$m=4kquad,quad kin Bbb N$$this is because $5^4=625equiv 1mod 16$ and therefore $$5^{4k}equiv5^{4k-4}equivcdots equiv 5^{4}equiv 1mod 16$$
Conclusion
All $n>5$s for which $5^n$ ends up with $3125$ can be found from $$n=4k+5quad,quad kin Bbb N$$ and the smallest such $n$ is 9.
answered 1 hour ago
Mostafa AyazMostafa Ayaz
17k3939
17k3939
add a comment |
add a comment |
$begingroup$
Hint: $5^n equiv 5^5 mod 10^4$ if and only if $5^n equiv 5^5 mod 2^4$. What is the multiplicative order of $5$ mod $16$?
$endgroup$
add a comment |
$begingroup$
Hint: $5^n equiv 5^5 mod 10^4$ if and only if $5^n equiv 5^5 mod 2^4$. What is the multiplicative order of $5$ mod $16$?
$endgroup$
add a comment |
$begingroup$
Hint: $5^n equiv 5^5 mod 10^4$ if and only if $5^n equiv 5^5 mod 2^4$. What is the multiplicative order of $5$ mod $16$?
$endgroup$
Hint: $5^n equiv 5^5 mod 10^4$ if and only if $5^n equiv 5^5 mod 2^4$. What is the multiplicative order of $5$ mod $16$?
answered 2 hours ago
Robert IsraelRobert Israel
328k23216469
328k23216469
add a comment |
add a comment |
$begingroup$
Well
$$5^9=1953125$$
so the answer is $9$. In fact
$$5^nequiv 5^{n-4} mod{10^4}$$
For $nge 8$, so any value of $5^{5+4k}$ where $kinmathbb{N}$ has the last four digits $3125$.
$endgroup$
$begingroup$
Why not $5^5 = 3125$.
$endgroup$
– fleablood
1 hour ago
1
$begingroup$
The question states that $ngt5$
$endgroup$
– Peter Foreman
1 hour ago
add a comment |
$begingroup$
Well
$$5^9=1953125$$
so the answer is $9$. In fact
$$5^nequiv 5^{n-4} mod{10^4}$$
For $nge 8$, so any value of $5^{5+4k}$ where $kinmathbb{N}$ has the last four digits $3125$.
$endgroup$
$begingroup$
Why not $5^5 = 3125$.
$endgroup$
– fleablood
1 hour ago
1
$begingroup$
The question states that $ngt5$
$endgroup$
– Peter Foreman
1 hour ago
add a comment |
$begingroup$
Well
$$5^9=1953125$$
so the answer is $9$. In fact
$$5^nequiv 5^{n-4} mod{10^4}$$
For $nge 8$, so any value of $5^{5+4k}$ where $kinmathbb{N}$ has the last four digits $3125$.
$endgroup$
Well
$$5^9=1953125$$
so the answer is $9$. In fact
$$5^nequiv 5^{n-4} mod{10^4}$$
For $nge 8$, so any value of $5^{5+4k}$ where $kinmathbb{N}$ has the last four digits $3125$.
edited 1 hour ago
answered 2 hours ago
Peter ForemanPeter Foreman
3,8371216
3,8371216
$begingroup$
Why not $5^5 = 3125$.
$endgroup$
– fleablood
1 hour ago
1
$begingroup$
The question states that $ngt5$
$endgroup$
– Peter Foreman
1 hour ago
add a comment |
$begingroup$
Why not $5^5 = 3125$.
$endgroup$
– fleablood
1 hour ago
1
$begingroup$
The question states that $ngt5$
$endgroup$
– Peter Foreman
1 hour ago
$begingroup$
Why not $5^5 = 3125$.
$endgroup$
– fleablood
1 hour ago
$begingroup$
Why not $5^5 = 3125$.
$endgroup$
– fleablood
1 hour ago
1
1
$begingroup$
The question states that $ngt5$
$endgroup$
– Peter Foreman
1 hour ago
$begingroup$
The question states that $ngt5$
$endgroup$
– Peter Foreman
1 hour ago
add a comment |
$begingroup$
Hint $ 5^{large 5+N}! bmod 10^{large 4} = 5^{large 5}(5^{largecolor{#c00} N}! bmod 2^{large 4}),,$ and $ 5^{largecolor{#c00} 4}equiv 1^{largecolor{#c00} 4}! pmod{!4^{large 2}},$ by $,5 equiv 1pmod{! color{#c00}4} $
$endgroup$
add a comment |
$begingroup$
Hint $ 5^{large 5+N}! bmod 10^{large 4} = 5^{large 5}(5^{largecolor{#c00} N}! bmod 2^{large 4}),,$ and $ 5^{largecolor{#c00} 4}equiv 1^{largecolor{#c00} 4}! pmod{!4^{large 2}},$ by $,5 equiv 1pmod{! color{#c00}4} $
$endgroup$
add a comment |
$begingroup$
Hint $ 5^{large 5+N}! bmod 10^{large 4} = 5^{large 5}(5^{largecolor{#c00} N}! bmod 2^{large 4}),,$ and $ 5^{largecolor{#c00} 4}equiv 1^{largecolor{#c00} 4}! pmod{!4^{large 2}},$ by $,5 equiv 1pmod{! color{#c00}4} $
$endgroup$
Hint $ 5^{large 5+N}! bmod 10^{large 4} = 5^{large 5}(5^{largecolor{#c00} N}! bmod 2^{large 4}),,$ and $ 5^{largecolor{#c00} 4}equiv 1^{largecolor{#c00} 4}! pmod{!4^{large 2}},$ by $,5 equiv 1pmod{! color{#c00}4} $
answered 38 mins ago
Bill DubuqueBill Dubuque
212k29195654
212k29195654
add a comment |
add a comment |
Catherine Cooper is a new contributor. Be nice, and check out our Code of Conduct.
Catherine Cooper is a new contributor. Be nice, and check out our Code of Conduct.
Catherine Cooper is a new contributor. Be nice, and check out our Code of Conduct.
Catherine Cooper is a new contributor. Be nice, and check out our Code of Conduct.
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1
$begingroup$
What is your take on this?
$endgroup$
– ADITYA PRAKASH
2 hours ago
1
$begingroup$
Why not just list them out and find it?
$endgroup$
– Jair Taylor
2 hours ago
3
$begingroup$
Why not just do it? It's not $1$ because $5^1=5$. It's not $2$ because $5^2 = 25$. What's to keep you from just continuing?
$endgroup$
– fleablood
1 hour ago