Truth table with logical gates for a traffic light Announcing the arrival of Valued Associate...
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Truth table with logical gates for a traffic light
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Writing down logic of a circuitCreate a CMOS circuit from a logic functionSR Latch/Racing?What operation does this circuit perform?Output of XOR gate with high-impedance inputLogic Gates - Did I connect them correctly?NAND Gate Logic OptimizationBit counter using basic logic gatesBuild Truth Table given CircuitCreate a circuit with max 6 NAND gates
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$begingroup$
I want to create this truth table:
So I tried this but I was not able to get the last row, which is:
While a =1 and b =1 ,yellow = 1 red = 0 and green = 0.
This is my design for it, but I could not make the last row.
Does anyone have a sample or a tip about what I can do to fix this?
Thanks!
logic-gates simulink
edited 1 hour ago
Niteesh Shanbog
513416
asked 1 hour ago
John wiliamJohn wiliam
162
New contributor
John wiliam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
I want to create this truth table:
So I tried this but I was not able to get the last row, which is:
While a =1 and b =1 ,yellow = 1 red = 0 and green = 0.
This is my design for it, but I could not make the last row.
Does anyone have a sample or a tip about what I can do to fix this?
Thanks!
logic-gates simulink
edited 1 hour ago
Niteesh Shanbog
513416
asked 1 hour ago
John wiliamJohn wiliam
162
New contributor
John wiliam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
$begingroup$
I remember doing a traffic light problem like this in one of my school labs.
$endgroup$
– user4574
19 mins ago
add a comment |
$begingroup$
I want to create this truth table:
So I tried this but I was not able to get the last row, which is:
While a =1 and b =1 ,yellow = 1 red = 0 and green = 0.
This is my design for it, but I could not make the last row.
Does anyone have a sample or a tip about what I can do to fix this?
Thanks!
logic-gates simulink
edited 1 hour ago
Niteesh Shanbog
513416
asked 1 hour ago
John wiliamJohn wiliam
162
New contributor
John wiliam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
I want to create this truth table:
So I tried this but I was not able to get the last row, which is:
While a =1 and b =1 ,yellow = 1 red = 0 and green = 0.
This is my design for it, but I could not make the last row.
Does anyone have a sample or a tip about what I can do to fix this?
Thanks!
logic-gates simulink
logic-gates simulink
edited 1 hour ago
Niteesh Shanbog
513416
asked 1 hour ago
John wiliamJohn wiliam
162
New contributor
John wiliam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 1 hour ago
Niteesh Shanbog
513416
asked 1 hour ago
John wiliamJohn wiliam
162
New contributor
John wiliam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 1 hour ago
Niteesh Shanbog
513416
edited 1 hour ago
Niteesh Shanbog
513416
edited 1 hour ago
Niteesh Shanbog
513416
513416
asked 1 hour ago
John wiliamJohn wiliam
162
New contributor
John wiliam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 1 hour ago
John wiliamJohn wiliam
162
asked 1 hour ago
John wiliamJohn wiliam
162
162
New contributor
John wiliam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
John wiliam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
John wiliam is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$begingroup$
I remember doing a traffic light problem like this in one of my school labs.
$endgroup$
– user4574
19 mins ago
add a comment |
$begingroup$
I remember doing a traffic light problem like this in one of my school labs.
$endgroup$
– user4574
19 mins ago
$begingroup$
I remember doing a traffic light problem like this in one of my school labs.
$endgroup$
– user4574
19 mins ago
$begingroup$
I remember doing a traffic light problem like this in one of my school labs.
$endgroup$
– user4574
19 mins ago
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
You can write the equations easily from the truth table
$$Red = bar A $$
$$Yellow = B$$
$$Green = A land bar B$$
They can be built the following circuit:
answered 1 hour ago
RenanRenan
4,34222244
$endgroup$
1
$begingroup$
thanks for the picture :)
$endgroup$
– John wiliam
1 hour ago
add a comment |
$begingroup$
YELLOW = $B$.
RED = $bar A$.
GREEN = $overline {RED + YELLOW}$
Purple is the implied logic for the red light, orange is the implied logic for the yellow light and green is for the green light.
One OR gate and two inverters would do the trick.
answered 1 hour ago
Andy akaAndy aka
244k11186425
$endgroup$
$begingroup$
thanks i do not know know much about the gates i i were trying too much things thanks for helping :) i solve it
$endgroup$
– John wiliam
1 hour ago
add a comment |
Your Answer
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
You can write the equations easily from the truth table
$$Red = bar A $$
$$Yellow = B$$
$$Green = A land bar B$$
They can be built the following circuit:
answered 1 hour ago
RenanRenan
4,34222244
$endgroup$
1
$begingroup$
thanks for the picture :)
$endgroup$
– John wiliam
1 hour ago
add a comment |
$begingroup$
You can write the equations easily from the truth table
$$Red = bar A $$
$$Yellow = B$$
$$Green = A land bar B$$
They can be built the following circuit:
answered 1 hour ago
RenanRenan
4,34222244
$endgroup$
1
$begingroup$
thanks for the picture :)
$endgroup$
– John wiliam
1 hour ago
add a comment |
$begingroup$
You can write the equations easily from the truth table
$$Red = bar A $$
$$Yellow = B$$
$$Green = A land bar B$$
They can be built the following circuit:
answered 1 hour ago
RenanRenan
4,34222244
$endgroup$
You can write the equations easily from the truth table
$$Red = bar A $$
$$Yellow = B$$
$$Green = A land bar B$$
They can be built the following circuit:
answered 1 hour ago
RenanRenan
4,34222244
answered 1 hour ago
RenanRenan
4,34222244
answered 1 hour ago
RenanRenan
4,34222244
answered 1 hour ago
RenanRenan
4,34222244
4,34222244
1
$begingroup$
thanks for the picture :)
$endgroup$
– John wiliam
1 hour ago
add a comment |
1
$begingroup$
thanks for the picture :)
$endgroup$
– John wiliam
1 hour ago
1
1
$begingroup$
thanks for the picture :)
$endgroup$
– John wiliam
1 hour ago
$begingroup$
thanks for the picture :)
$endgroup$
– John wiliam
1 hour ago
add a comment |
$begingroup$
YELLOW = $B$.
RED = $bar A$.
GREEN = $overline {RED + YELLOW}$
Purple is the implied logic for the red light, orange is the implied logic for the yellow light and green is for the green light.
One OR gate and two inverters would do the trick.
answered 1 hour ago
Andy akaAndy aka
244k11186425
$endgroup$
$begingroup$
thanks i do not know know much about the gates i i were trying too much things thanks for helping :) i solve it
$endgroup$
– John wiliam
1 hour ago
add a comment |
$begingroup$
YELLOW = $B$.
RED = $bar A$.
GREEN = $overline {RED + YELLOW}$
Purple is the implied logic for the red light, orange is the implied logic for the yellow light and green is for the green light.
One OR gate and two inverters would do the trick.
answered 1 hour ago
Andy akaAndy aka
244k11186425
$endgroup$
$begingroup$
thanks i do not know know much about the gates i i were trying too much things thanks for helping :) i solve it
$endgroup$
– John wiliam
1 hour ago
add a comment |
$begingroup$
YELLOW = $B$.
RED = $bar A$.
GREEN = $overline {RED + YELLOW}$
Purple is the implied logic for the red light, orange is the implied logic for the yellow light and green is for the green light.
One OR gate and two inverters would do the trick.
answered 1 hour ago
Andy akaAndy aka
244k11186425
$endgroup$
YELLOW = $B$.
RED = $bar A$.
GREEN = $overline {RED + YELLOW}$
Purple is the implied logic for the red light, orange is the implied logic for the yellow light and green is for the green light.
One OR gate and two inverters would do the trick.
answered 1 hour ago
Andy akaAndy aka
244k11186425
edited 1 hour ago
answered 1 hour ago
Andy akaAndy aka
244k11186425
answered 1 hour ago
Andy akaAndy aka
244k11186425
answered 1 hour ago
Andy akaAndy aka
244k11186425
244k11186425
$begingroup$
thanks i do not know know much about the gates i i were trying too much things thanks for helping :) i solve it
$endgroup$
– John wiliam
1 hour ago
add a comment |
$begingroup$
thanks i do not know know much about the gates i i were trying too much things thanks for helping :) i solve it
$endgroup$
– John wiliam
1 hour ago
$begingroup$
thanks i do not know know much about the gates i i were trying too much things thanks for helping :) i solve it
$endgroup$
– John wiliam
1 hour ago
$begingroup$
thanks i do not know know much about the gates i i were trying too much things thanks for helping :) i solve it
$endgroup$
– John wiliam
1 hour ago
add a comment |
John wiliam is a new contributor. Be nice, and check out our Code of Conduct.
John wiliam is a new contributor. Be nice, and check out our Code of Conduct.
John wiliam is a new contributor. Be nice, and check out our Code of Conduct.
John wiliam is a new contributor. Be nice, and check out our Code of Conduct.
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$begingroup$
I remember doing a traffic light problem like this in one of my school labs.
$endgroup$
– user4574
19 mins ago