Using only 1s, make 29 with the minimum number of digitsMaking π from 1 2 3 4 5 6 7 8 9Express the number...
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Using only 1s, make 29 with the minimum number of digits
Making π from 1 2 3 4 5 6 7 8 9Express the number $2015$ using only the digit $2$ twiceHow many consecutive positive integers can you make using exactly four instances of the digit '4'?Make numbers 1 - 32 using the digits 2, 0, 1, 7Most consecutive positive integers using two 1sMake numbers 1-31 with 1,9,7,8Make numbers 1 - 30 using the digits 2, 0, 1, 8Make numbers 93 using the digits 2, 0, 1, 8Make numbers 33-100 using only digits 2,0,1,8Make numbers 1-30 using 2, 0, 1, 9
$begingroup$
Operations permitted:
- Standard operations: +, −, ×, ÷
- Negation: −
- Exponentiation of two numbers: x^y
- Square root of a number: √
- Factorial: !
- Concatenation of the original digits: dd
mathematics calculation-puzzle formation-of-numbers
asked 35 mins ago
Allan CaoAllan Cao
1063
New contributor
Allan Cao is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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$endgroup$
add a comment |
$begingroup$
Operations permitted:
- Standard operations: +, −, ×, ÷
- Negation: −
- Exponentiation of two numbers: x^y
- Square root of a number: √
- Factorial: !
- Concatenation of the original digits: dd
mathematics calculation-puzzle formation-of-numbers
asked 35 mins ago
Allan CaoAllan Cao
1063
New contributor
Allan Cao is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
Operations permitted:
- Standard operations: +, −, ×, ÷
- Negation: −
- Exponentiation of two numbers: x^y
- Square root of a number: √
- Factorial: !
- Concatenation of the original digits: dd
mathematics calculation-puzzle formation-of-numbers
asked 35 mins ago
Allan CaoAllan Cao
1063
New contributor
Allan Cao is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
Operations permitted:
- Standard operations: +, −, ×, ÷
- Negation: −
- Exponentiation of two numbers: x^y
- Square root of a number: √
- Factorial: !
- Concatenation of the original digits: dd
mathematics calculation-puzzle formation-of-numbers
mathematics calculation-puzzle formation-of-numbers
asked 35 mins ago
Allan CaoAllan Cao
1063
New contributor
Allan Cao is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 35 mins ago
Allan CaoAllan Cao
1063
New contributor
Allan Cao is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 35 mins ago
Allan CaoAllan Cao
1063
New contributor
Allan Cao is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 35 mins ago
Allan CaoAllan Cao
1063
asked 35 mins ago
Allan CaoAllan Cao
1063
1063
New contributor
Allan Cao is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Allan Cao is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Allan Cao is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
Here's a 7 digits solution:
7 digits: (11-1)x(1+1+1)-1
answered 12 mins ago
Dr XorileDr Xorile
12.9k22569
$endgroup$
$begingroup$
That is the minimum I achieved by referencing the Single Digit Representations of Natural Numbers paper. Hopefully 6 is possible.
$endgroup$
– Allan Cao
2 mins ago
add a comment |
$begingroup$
Lowest I managed so far is 9 digits:
(1 + 1 + 1 + 1)! + 1 + 1 + 1 + 1 + 1
11*(1 + 1 + 1) - (1 + 1 + 1 + 1)
Some other ways I came up with:
(1 + 1)^(1 + 1 + 1 + 1 + 1) - 1 - 1 - 1 (10 digits)
(1 + 1 + 1 + 1 + 1)!/(1 + 1 + 1 + 1) - 1 (10 digits)
(1 + 1 + 1 + 1 + 1)^(1 + 1) + 1 + 1 + 1 + 1 (11 digits)
11*(1 + 1) + 1 + 1 + 1 + 1 + 1 + 1 + 1 (11 digits)
answered 22 mins ago
simonzacksimonzack
267110
$endgroup$
add a comment |
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2 Answers
2
active
oldest
votes
2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Here's a 7 digits solution:
7 digits: (11-1)x(1+1+1)-1
answered 12 mins ago
Dr XorileDr Xorile
12.9k22569
$endgroup$
$begingroup$
That is the minimum I achieved by referencing the Single Digit Representations of Natural Numbers paper. Hopefully 6 is possible.
$endgroup$
– Allan Cao
2 mins ago
add a comment |
$begingroup$
Here's a 7 digits solution:
7 digits: (11-1)x(1+1+1)-1
answered 12 mins ago
Dr XorileDr Xorile
12.9k22569
$endgroup$
$begingroup$
That is the minimum I achieved by referencing the Single Digit Representations of Natural Numbers paper. Hopefully 6 is possible.
$endgroup$
– Allan Cao
2 mins ago
add a comment |
$begingroup$
Here's a 7 digits solution:
7 digits: (11-1)x(1+1+1)-1
answered 12 mins ago
Dr XorileDr Xorile
12.9k22569
$endgroup$
Here's a 7 digits solution:
7 digits: (11-1)x(1+1+1)-1
answered 12 mins ago
Dr XorileDr Xorile
12.9k22569
answered 12 mins ago
Dr XorileDr Xorile
12.9k22569
answered 12 mins ago
Dr XorileDr Xorile
12.9k22569
answered 12 mins ago
Dr XorileDr Xorile
12.9k22569
12.9k22569
$begingroup$
That is the minimum I achieved by referencing the Single Digit Representations of Natural Numbers paper. Hopefully 6 is possible.
$endgroup$
– Allan Cao
2 mins ago
add a comment |
$begingroup$
That is the minimum I achieved by referencing the Single Digit Representations of Natural Numbers paper. Hopefully 6 is possible.
$endgroup$
– Allan Cao
2 mins ago
$begingroup$
That is the minimum I achieved by referencing the Single Digit Representations of Natural Numbers paper. Hopefully 6 is possible.
$endgroup$
– Allan Cao
2 mins ago
$begingroup$
That is the minimum I achieved by referencing the Single Digit Representations of Natural Numbers paper. Hopefully 6 is possible.
$endgroup$
– Allan Cao
2 mins ago
add a comment |
$begingroup$
Lowest I managed so far is 9 digits:
(1 + 1 + 1 + 1)! + 1 + 1 + 1 + 1 + 1
11*(1 + 1 + 1) - (1 + 1 + 1 + 1)
Some other ways I came up with:
(1 + 1)^(1 + 1 + 1 + 1 + 1) - 1 - 1 - 1 (10 digits)
(1 + 1 + 1 + 1 + 1)!/(1 + 1 + 1 + 1) - 1 (10 digits)
(1 + 1 + 1 + 1 + 1)^(1 + 1) + 1 + 1 + 1 + 1 (11 digits)
11*(1 + 1) + 1 + 1 + 1 + 1 + 1 + 1 + 1 (11 digits)
answered 22 mins ago
simonzacksimonzack
267110
$endgroup$
add a comment |
$begingroup$
Lowest I managed so far is 9 digits:
(1 + 1 + 1 + 1)! + 1 + 1 + 1 + 1 + 1
11*(1 + 1 + 1) - (1 + 1 + 1 + 1)
Some other ways I came up with:
(1 + 1)^(1 + 1 + 1 + 1 + 1) - 1 - 1 - 1 (10 digits)
(1 + 1 + 1 + 1 + 1)!/(1 + 1 + 1 + 1) - 1 (10 digits)
(1 + 1 + 1 + 1 + 1)^(1 + 1) + 1 + 1 + 1 + 1 (11 digits)
11*(1 + 1) + 1 + 1 + 1 + 1 + 1 + 1 + 1 (11 digits)
answered 22 mins ago
simonzacksimonzack
267110
$endgroup$
add a comment |
$begingroup$
Lowest I managed so far is 9 digits:
(1 + 1 + 1 + 1)! + 1 + 1 + 1 + 1 + 1
11*(1 + 1 + 1) - (1 + 1 + 1 + 1)
Some other ways I came up with:
(1 + 1)^(1 + 1 + 1 + 1 + 1) - 1 - 1 - 1 (10 digits)
(1 + 1 + 1 + 1 + 1)!/(1 + 1 + 1 + 1) - 1 (10 digits)
(1 + 1 + 1 + 1 + 1)^(1 + 1) + 1 + 1 + 1 + 1 (11 digits)
11*(1 + 1) + 1 + 1 + 1 + 1 + 1 + 1 + 1 (11 digits)
answered 22 mins ago
simonzacksimonzack
267110
$endgroup$
Lowest I managed so far is 9 digits:
(1 + 1 + 1 + 1)! + 1 + 1 + 1 + 1 + 1
11*(1 + 1 + 1) - (1 + 1 + 1 + 1)
Some other ways I came up with:
(1 + 1)^(1 + 1 + 1 + 1 + 1) - 1 - 1 - 1 (10 digits)
(1 + 1 + 1 + 1 + 1)!/(1 + 1 + 1 + 1) - 1 (10 digits)
(1 + 1 + 1 + 1 + 1)^(1 + 1) + 1 + 1 + 1 + 1 (11 digits)
11*(1 + 1) + 1 + 1 + 1 + 1 + 1 + 1 + 1 (11 digits)
answered 22 mins ago
simonzacksimonzack
267110
edited 14 mins ago
answered 22 mins ago
simonzacksimonzack
267110
answered 22 mins ago
simonzacksimonzack
267110
answered 22 mins ago
simonzacksimonzack
267110
267110
add a comment |
add a comment |
Allan Cao is a new contributor. Be nice, and check out our Code of Conduct.
Allan Cao is a new contributor. Be nice, and check out our Code of Conduct.
Allan Cao is a new contributor. Be nice, and check out our Code of Conduct.
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