Rearrange c++ const and reference specifiers The Next CEO of Stack OverflowCreating a regex to...
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Rearrange c++ const and reference specifiers
The Next CEO of Stack OverflowCreating a regex to match html attributesSearch all mention of the current file's file nameIs there a way to convert a Vim regex literal to different magic modes?Recognizing expression written in assembly containing $ and new lineRegex to match any character including newlineNewline in sub-replace expressionBreak-down long strings and search/replace individual wordsloading back-reference groups “shortcut”regex find and replace all with capture groups throws E488: Trailing charactersUsing (neo)vim's regex to match up to but *excluding* a certain character?
I'm trying to convert
const std::string &s
to
std::string const & s
and can't seem to get it quite right. This is the regex I'm using:
%s/const (.{-}) &/1 const &
and the result I'm getting:
std::string const const std::string &s
regular-expression c++
asked 5 hours ago
Jay MuellerJay Mueller
82
New contributor
Jay Mueller is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
I'm trying to convert
const std::string &s
to
std::string const & s
and can't seem to get it quite right. This is the regex I'm using:
%s/const (.{-}) &/1 const &
and the result I'm getting:
std::string const const std::string &s
regular-expression c++
asked 5 hours ago
Jay MuellerJay Mueller
82
New contributor
Jay Mueller is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
I'm trying to convert
const std::string &s
to
std::string const & s
and can't seem to get it quite right. This is the regex I'm using:
%s/const (.{-}) &/1 const &
and the result I'm getting:
std::string const const std::string &s
regular-expression c++
asked 5 hours ago
Jay MuellerJay Mueller
82
New contributor
Jay Mueller is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I'm trying to convert
const std::string &s
to
std::string const & s
and can't seem to get it quite right. This is the regex I'm using:
%s/const (.{-}) &/1 const &
and the result I'm getting:
std::string const const std::string &s
regular-expression c++
regular-expression c++
asked 5 hours ago
Jay MuellerJay Mueller
82
New contributor
Jay Mueller is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 5 hours ago
Jay MuellerJay Mueller
82
New contributor
Jay Mueller is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 5 hours ago
Jay MuellerJay Mueller
82
New contributor
Jay Mueller is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 5 hours ago
Jay MuellerJay Mueller
82
asked 5 hours ago
Jay MuellerJay Mueller
82
82
New contributor
Jay Mueller is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Jay Mueller is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Jay Mueller is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
1 Answer
1
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oldest
votes
Just escape the & with a backslash.
%s/const (.{-}) &/1 const &
The & in the replace part inserts the entire matched pattern.
See :help s/&.
answered 4 hours ago
RalfRalf
3,1551317
add a comment |
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1 Answer
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1 Answer
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active
oldest
votes
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oldest
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active
oldest
votes
Just escape the & with a backslash.
%s/const (.{-}) &/1 const &
The & in the replace part inserts the entire matched pattern.
See :help s/&.
answered 4 hours ago
RalfRalf
3,1551317
add a comment |
Just escape the & with a backslash.
%s/const (.{-}) &/1 const &
The & in the replace part inserts the entire matched pattern.
See :help s/&.
answered 4 hours ago
RalfRalf
3,1551317
add a comment |
Just escape the & with a backslash.
%s/const (.{-}) &/1 const &
The & in the replace part inserts the entire matched pattern.
See :help s/&.
answered 4 hours ago
RalfRalf
3,1551317
Just escape the & with a backslash.
%s/const (.{-}) &/1 const &
The & in the replace part inserts the entire matched pattern.
See :help s/&.
answered 4 hours ago
RalfRalf
3,1551317
answered 4 hours ago
RalfRalf
3,1551317
answered 4 hours ago
RalfRalf
3,1551317
answered 4 hours ago
RalfRalf
3,1551317
3,1551317
add a comment |
add a comment |
Jay Mueller is a new contributor. Be nice, and check out our Code of Conduct.
Jay Mueller is a new contributor. Be nice, and check out our Code of Conduct.
Jay Mueller is a new contributor. Be nice, and check out our Code of Conduct.
Jay Mueller is a new contributor. Be nice, and check out our Code of Conduct.
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